Python 在Django中加载具有不同数据的相同模板时，如何防止url更改

我有一个简单的def，有这样的东西

def policies_index(request):
    """Resource listing"""
    policies = Policy.objects.all()
    context = {
        'policies' : policies
    }
    return render(request, "policies/index.html", context)

def policies_date_filter(request):
    """List the resources based on a month year filter"""
    today = datetime.date.today()
    year = request.POST['year']
    month = request.POST['month']
    policies = Policy.objects.filter(end_date__year=year).filter(end_date__month=month)
    status = settings.POLICY_STATUS_SELECT
    for policy in policies:
        for status_name in status:
            if status_name['value'] == policy.status:
                policy.status_name = status_name['name']
    request.policies = policies

    return policies_index(request)

 def policies_index(request):
    """Resource listing"""

    #If method == POST it means is the filter function so I change the policies queryset
    if request.method == "POST":
        year = request.POST['year']
        month = request.POST['month']
        policies = Policy.objects.filter(end_date__year=year).filter(end_date__month=month)
    else:
        policies = Policy.objects.all()

    context = {
        'policies' : policies,
    }
    return render(request, "policies/index.html", context)

现在我想添加一种方法，使用月份和年份过滤这些信息，所以我制作了一个类似这样的函数

def policies_index(request):
    """Resource listing"""
    policies = Policy.objects.all()
    context = {
        'policies' : policies
    }
    return render(request, "policies/index.html", context)

def policies_date_filter(request):
    """List the resources based on a month year filter"""
    today = datetime.date.today()
    year = request.POST['year']
    month = request.POST['month']
    policies = Policy.objects.filter(end_date__year=year).filter(end_date__month=month)
    status = settings.POLICY_STATUS_SELECT
    for policy in policies:
        for status_name in status:
            if status_name['value'] == policy.status:
                policy.status_name = status_name['name']
    request.policies = policies

    return policies_index(request)

 def policies_index(request):
    """Resource listing"""

    #If method == POST it means is the filter function so I change the policies queryset
    if request.method == "POST":
        year = request.POST['year']
        month = request.POST['month']
        policies = Policy.objects.filter(end_date__year=year).filter(end_date__month=month)
    else:
        policies = Policy.objects.all()

    context = {
        'policies' : policies,
    }
    return render(request, "policies/index.html", context)

这样我就可以重用函数索引，避免编写再次打印视图的代码，而且效果很好，但是在url中，而不是像“/policies”这样的内容，我得到了像“/policies/datefilter”这样的内容

---

这是有意义的，因为我调用了另一个函数，有没有办法防止url更改？

哈哈，写这个问题我刚想出来我可以在视图中调用相同的函数，但是使用POST方法而不是GET，这样他们就可以保持相同的url，所以我最终得到了这样的结果

def policies_index(request):
    """Resource listing"""
    policies = Policy.objects.all()
    context = {
        'policies' : policies
    }
    return render(request, "policies/index.html", context)

def policies_date_filter(request):
    """List the resources based on a month year filter"""
    today = datetime.date.today()
    year = request.POST['year']
    month = request.POST['month']
    policies = Policy.objects.filter(end_date__year=year).filter(end_date__month=month)
    status = settings.POLICY_STATUS_SELECT
    for policy in policies:
        for status_name in status:
            if status_name['value'] == policy.status:
                policy.status_name = status_name['name']
    request.policies = policies

    return policies_index(request)

 def policies_index(request):
    """Resource listing"""

    #If method == POST it means is the filter function so I change the policies queryset
    if request.method == "POST":
        year = request.POST['year']
        month = request.POST['month']
        policies = Policy.objects.filter(end_date__year=year).filter(end_date__month=month)
    else:
        policies = Policy.objects.all()

    context = {
        'policies' : policies,
    }
    return render(request, "policies/index.html", context)

现在就像一个符咒，你们觉得呢？有更好的方法吗？我对Django有点陌生