Python 获取或创建方法上的django电话号码字段错误
我在Django模型的get_或_create方法上遇到错误,该方法包含PhoneNumberField(Django phonenumber field==1.3.0)字段 它以前工作得很好,因此我尝试了几个较旧的django phonenumber field(1.2.0、1.1.0、1.0.0)版本,但结果都是一样的 正在尝试做的事Python 获取或创建方法上的django电话号码字段错误,python,django,django-managers,Python,Django,Django Managers,我在Django模型的get_或_create方法上遇到错误,该方法包含PhoneNumberField(Django phonenumber field==1.3.0)字段 它以前工作得很好,因此我尝试了几个较旧的django phonenumber field(1.2.0、1.1.0、1.0.0)版本,但结果都是一样的 正在尝试做的事 TestModel.objects.get\u或\u create(name='testname') 型号.py from django.utils.tran
TestModel.objects.get\u或\u create(name='testname')
型号.py
from django.utils.translation import get_language, ugettext_lazy as _
from phonenumber_field.modelfields import PhoneNumberField
from django.db import models
class TestModel(models.Model):
name = models.CharField(max_length=20, blank=True,
null=True)
phone = PhoneNumberField(
_('Phone'), blank=True, unique=True, null=True,
help_text=_('Enter phone number...')
)
回溯
<ipython-input-3-03bfe9e47b71> in <module>()
----> 1 TestModel.objects.get_or_create(name='test')
/usr/local/lib/python3.5/site-packages/django/db/models/manager.py in manager_method(self, *args, **kwargs)
83 def create_method(name, method):
84 def manager_method(self, *args, **kwargs):
---> 85 return getattr(self.get_queryset(), name)(*args, **kwargs)
86 manager_method.__name__ = method.__name__
87 manager_method.__doc__ = method.__doc__
/usr/local/lib/python3.5/site-packages/django/db/models/query.py in get_or_create(self, defaults, **kwargs)
457 specifying whether an object was created.
458 """
--> 459 lookup, params = self._extract_model_params(defaults, **kwargs)
460 # The get() needs to be targeted at the write database in order
461 # to avoid potential transaction consistency problems.
/usr/local/lib/python3.5/site-packages/django/db/models/query.py in _extract_model_params(self, defaults, **kwargs)
519 params = {k: v for k, v in kwargs.items() if LOOKUP_SEP not in k}
520 params.update(defaults)
--> 521 property_names = self.model._meta._property_names
522 invalid_params = []
523 for param in params:
/usr/local/lib/python3.5/site-packages/django/utils/functional.py in __get__(self, instance, cls)
33 if instance is None:
34 return self
---> 35 res = instance.__dict__[self.name] = self.func(instance)
36 return res
37
/usr/local/lib/python3.5/site-packages/django/db/models/options.py in _property_names(self)
885 return frozenset({
886 attr for attr in
--> 887 dir(self.model) if isinstance(getattr(self.model, attr), property)
888 })
/usr/local/lib/python3.5/site-packages/django/db/models/options.py in <setcomp>(.0)
885 return frozenset({
886 attr for attr in
--> 887 dir(self.model) if isinstance(getattr(self.model, attr), property)
888 })
/usr/local/lib/python3.5/site-packages/phonenumber_field/modelfields.py in __get__(self, instance, owner)
31 raise AttributeError(
32 "The '%s' attribute can only be accessed from %s instances."
---> 33 % (self.field.name, owner.__name__))
34 return instance.__dict__[self.field.name]
35
AttributeError: The 'phone' attribute can only be accessed from TestModel instances.
()
---->1 TestModel.objects.get\u或\u create(name='test')
/manager_方法中的usr/local/lib/python3.5/site-packages/django/db/models/manager.py(self,*args,**kwargs)
83定义创建方法(名称、方法):
84 def管理器_方法(self、*args、**kwargs):
--->85返回getattr(self.get_queryset(),name)(*args,**kwargs)
86管理者\方法。\名称\方法。\名称__
87管理者方法。文件=方法。文件__
/get_或_create中的usr/local/lib/python3.5/site-packages/django/db/models/query.py(self,默认值,**kwargs)
457指定是否创建了对象。
458 """
-->459查找,参数=self._extract_model_params(默认值,**kwargs)
460#get()需要以写数据库为目标,以便
461#避免潜在的事务一致性问题。
/usr/local/lib/python3.5/site-packages/django/db/models/query.py in_extract_model_params(self,默认值,**kwargs)
519参数={k:v代表k,v在kwargs.items()中,如果查找不在k}
520参数更新(默认值)
-->521属性\u名称=self.model.\u meta.\u属性\u名称
522无效的_参数=[]
523对于参数中的参数:
/usr/local/lib/python3.5/site-packages/django/utils/functional.py in\uuuuuu get\uuuuu(self、instance、cls)
33如果实例为无:
34回归自我
--->35 res=instance.\uu dict\uu[self.name]=self.func(实例)
36返回res
37
/usr/local/lib/python3.5/site-packages/django/db/models/options.py in_property_names(self)
885回程防冻套({
886 attr用于attr in
-->887 dir(self.model)如果isinstance(getattr(self.model,attr),属性)
888 })
/usr/local/lib/python3.5/site-packages/django/db/models/options.py in(.0)
885回程防冻套({
886 attr用于attr in
-->887 dir(self.model)如果isinstance(getattr(self.model,attr),属性)
888 })
/usr/local/lib/python3.5/site-packages/phonenumber\u field/modelfields.py in\uuuuuuu get\uuuuuu(self、instance、owner)
31提高属性错误(
32“只能从%s实例访问'%s'属性。”
--->33%(self.field.name,owner.\uuuu name\uuuuu))
34返回实例。\u dict\u[self.field.name]
35
AttributeError:“phone”属性只能从TestModel实例访问。
Django版本1.11.2出现错误。Django 1.11.1工作正常。第一个参数是什么在
phone
字段中应该是?您没有将其分配给label
或help_text
之类的属性;它只是自己存在。您可以粘贴django版本吗?django版本1.11.2。生产正常,并且它使用django 1.11.1,我将在本地(“phone”)上测试它是字段的名称,我只是尝试在没有它的情况下获取_或_create,结果是相同的,可能它与红十字会在django=1.11,python=3.5附近有一些共同点(我不是在问而不是在回答)