Python 如何卸下';秒';熊猫数据帧索引?
给定一个具有如下所示时间序列的数据帧:Python 如何卸下';秒';熊猫数据帧索引?,python,pandas,time-series,dataframe,Python,Pandas,Time Series,Dataframe,给定一个具有如下所示时间序列的数据帧: Close 2015-02-20 14:00:00 1200.1 2015-02-20 14:10:00 1199.8 2015-02-21 14:00:00 1199.3 2015-02-21 14:10:00 1199.0 2015-02-22 14:00:00 1198.4 2015-02-22 14:10:00 1199.7 Close 2015-02-
Close
2015-02-20 14:00:00 1200.1
2015-02-20 14:10:00 1199.8
2015-02-21 14:00:00 1199.3
2015-02-21 14:10:00 1199.0
2015-02-22 14:00:00 1198.4
2015-02-22 14:10:00 1199.7
Close
2015-02-20 14:00 1200.1
2015-02-20 14:10 1199.8
2015-02-21 14:00 1199.3
2015-02-21 14:10 1199.0
2015-02-22 14:00 1198.4
2015-02-22 14:10 1199.7
df.index =df.index.map(lambda t: t.strftime('%Y-%m-%d %H:%M'))
如何去掉索引的“秒数”,使其看起来像这样:
Close
2015-02-20 14:00:00 1200.1
2015-02-20 14:10:00 1199.8
2015-02-21 14:00:00 1199.3
2015-02-21 14:10:00 1199.0
2015-02-22 14:00:00 1198.4
2015-02-22 14:10:00 1199.7
Close
2015-02-20 14:00 1200.1
2015-02-20 14:10 1199.8
2015-02-21 14:00 1199.3
2015-02-21 14:10 1199.0
2015-02-22 14:00 1198.4
2015-02-22 14:10 1199.7
df.index =df.index.map(lambda t: t.strftime('%Y-%m-%d %H:%M'))
谢谢您可以像这样使用
map
和strftime
:
Close
2015-02-20 14:00:00 1200.1
2015-02-20 14:10:00 1199.8
2015-02-21 14:00:00 1199.3
2015-02-21 14:10:00 1199.0
2015-02-22 14:00:00 1198.4
2015-02-22 14:10:00 1199.7
Close
2015-02-20 14:00 1200.1
2015-02-20 14:10 1199.8
2015-02-21 14:00 1199.3
2015-02-21 14:10 1199.0
2015-02-22 14:00 1198.4
2015-02-22 14:10 1199.7
df.index =df.index.map(lambda t: t.strftime('%Y-%m-%d %H:%M'))