如何根据python中的特定值将数组拆分为多个数组

假设我有一个随机值数组。在数组中有一个值接近0，但不是0，它在随机位置连续重复。我要做的是找到这些值，并在这个位置将数组拆分为多个数组，同时删除重复的值。限制是，如果连续重复的次数不超过两次，则无法消除该值

例如：

array=np.array([-0.005,-0.004,0.00002,-0.003,0.004,0.00002,0.00002,0.00002,0.00002,
            0.005,0.003,0.00002,0.0006,0.008,0.00002,0.00002,0.00002,
            -0.003,0.006,0.007,0.00002,0.00002,0.00002])
minval=np.abs(array).min()
print(minval)

我发现0.00002是最接近0的值，因此我的目标是获得：

array1=([-0.005,-0.004,0.00002,-0.003,0.004],[0.005,0.003,0.00002,0.0006,0.008],[-0.003,0.006,0.007])

---

在Python中有没有一种方便的方法可以做到这一点？

您可以这样做：

import numpy as np
array=np.array([-0.005,-0.004,0.00002,-0.003,0.004,0.00002,0.00002,0.00002,0.00002,
            0.005,0.003,0.00002,0.0006,0.008,0.00002,0.00002,0.00002,
            -0.003,0.006,0.007,0.00002,0.00002,0.00002])
absArr = np.abs(array)
min_val=absArr.min()
idx = np.where(absArr == min_val)[0]

grad= idx[1:] - idx[:-1]

arrs = []
for l,u,g in zip(idx[:-1],idx[1:],grad):
    print(l,u,g)
    if g > 1:
        arrs.append(array[l:u])

然后

arrs

有以下内容：

[[ 2.e-05 -3.e-03  4.e-03],
[2.e-05 5.e-03 3.e-03],
[2.e-05 6.e-04 8.e-03],
[ 2.e-05 -3.e-03  6.e-03  7.e-03]]

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使用迭代器可以相对轻松地实现这一点：

将numpy导入为np
def按最小值拆分（arr）：
equals=np.isclose（arr，np.abs（arr）.min（））
l=[]
准备好了吗
对于范围内的i（len（arr））：
如果等于[i]且i

输出：

[-0.005, -0.004, 2e-05, -0.003, 0.004]
[0.005, 0.003, 2e-05, 0.0006, 0.008]
[-0.003, 0.006, 0.007]

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您的输出是否与您的限制一致？限制是，如果连续重复的次数不超过两次，则无法消除该值？如果我理解第二个数组

0.3,0.4,0.2,0.5.0.3

？您应该描述您为解决此任务所做的工作。哪些工作和哪些工作不起作用。通过这种方式，其他用户可以更好地帮助您在发布任务之前进行基础研究。谢谢你的理解