R-如何筛选出具有唯一标识符的重复数据？

我有一个数据集是调查数据。如果我使用distinct（x），代码将不会读取任何重复项，因为我有一个“Survey ID”列，该列将始终不同

x <- data.frame("Survey ID" = 1001:1008,
                "First Initial" = c("M","P","S","B","H", "P", "L", "A"),
                "Last Initial" = c("S","J", "A", "P", "Q", "J", "P", "C"),
                "Age" = c(34,41,52,61,25,41,19,58),
                "Gender" = c("M", "M", "M", "F","M","M","F","M"),
                "Ethnicity" = c(2,2,1,1,3,2,1,4),
                "Veteran Status" = c("A","Y","N","Y","N","Y","N","N")
                )

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x我们可以在

library(dplyr)
x %>%
    distinct_at(-1, .keep_all = TRUE)

如果要指定列名

x %>%
  distinct_at(vars(Age, Gender), .keep_all = TRUE)

---

或者另一个选项是

unique

from

data.table

library(data.table)
unique(setDT(x), by = names(x)[-1])

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也可以对除第一列以外的所有列执行以下操作：

x[!duplicated(x[,-1]),]

或对于选定列：

x[!duplicated(x[,c("Age","Gender"),])

---

两者都将保留第一个复制行。

这太完美了！如果我只想过滤某些列呢？就像我的数据集x中的“年龄”和“性别”列一样？谢谢，这太棒了！我真的很感谢你的帮助！

x[!duplicated(x[,c("Age","Gender"),])