当差异为<；时，将状态值更改为1；0英寸r
当Diff值小于0时，我试图更新数据集中的Status列，因此当Diff值为-neg数字时，我希望Status列=1以表示更改。 下面是我的数据集的示例代码，全部为数字：当差异为<；时，将状态值更改为1；0英寸r,r,for-loop,dplyr,R,For Loop,Dplyr,当Diff值小于0时，我试图更新数据集中的Status列，因此当Diff值为-neg数字时，我希望Status列=1以表示更改。 下面是我的数据集的示例代码，全部为数字： df <- as.data.frame(list(diff=c("4","0","0","0","0","0","0","0","0","0", "0","-30","0","0","0","0","0","0","0","0",
df <- as.data.frame(list(diff=c("4","0","0","0","0","0","0","0","0","0",
"0","-30","0","0","0","0","0","0","0","0",
"14","0","0","0","0","0","0","-55","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","-40","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","-30","0","0","0","0","0","0","0","0",
"0","0","0","0","0"),
status=c("0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0")))
dflibrary（dplyr）
df%
变异（状态=ifelse（差异<0,1,0））
您为data.frame函数提供了一组字符值，这造成了一个难题。默认情况下，这将创建因子变量，除非您设置stringsAsFactors=FALSE
。有两件事是重要的：与0的比较将失败，而对df$status列中不存在的值的赋值也将失败
df <- data.frame(diff=c("4","0","0","0","0","0","0","0","0","0",
"0","-30","0","0","0","0","0","0","0","0",
"14","0","0","0","0","0","0","-55","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","-40","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","-30","0","0","0","0","0","0","0","0",
"0","0","0","0","0"),
status=c("0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0"), stringsAsFactors=FALSE)
df你能解释一下这段代码是如何解决问题的吗？虽然这段代码可能会解决问题，但这段代码是如何解决问题的，以及为什么它会真正有助于提高你的文章质量，并可能导致更多的投票。请记住，你是在将来回答读者的问题，而不仅仅是现在提问的人。请编辑您的答案以添加解释，并指出适用的限制和假设。谢谢Joseph，这是一个梦想，有一件事我必须先删除NA的值，这样我就不会得到任何错误。我认为代码实际上不起作用。本应预计差异列的因子性质会导致数值比较出现问题。。。的确如此。
df <- data.frame(diff=c("4","0","0","0","0","0","0","0","0","0",
"0","-30","0","0","0","0","0","0","0","0",
"14","0","0","0","0","0","0","-55","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","-40","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","-30","0","0","0","0","0","0","0","0",
"0","0","0","0","0"),
status=c("0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0","0","0","0","0","0",
"0","0","0","0","0"), stringsAsFactors=FALSE)
df$status[as.numeric(df$diff) < 0 ] <- 1