R 如何使用标记中的循环在一个块中呈现多个'quick'对象?
我想在一个块中使用循环渲染库R 如何使用标记中的循环在一个块中呈现多个'quick'对象?,r,markdown,learnr,R,Markdown,Learnr,我想在一个块中使用循环渲染库learnr的函数quick的多个对象。R正在编译html标记文件,但呈现不正确。它是在呈现文本,而不是一个应该是的问题 这是我的可复制代码,当前未正确呈现: --- title: "" output: learnr::tutorial runtime: shiny_prerendered description: "" --- ```{r setup, include=FALSE} knitr::opts_chunk$set(
learnr
的函数quick
的多个对象。R
正在编译html标记
文件,但呈现不正确。它是在呈现文本,而不是一个应该是的问题
这是我的可复制代码,当前未正确呈现:
---
title: ""
output: learnr::tutorial
runtime: shiny_prerendered
description: ""
---
```{r setup, include=FALSE}
knitr::opts_chunk$set(echo = FALSE)
library(learnr)
```
```{r, q-part2, echo=FALSE, results='asis'}
words_lst <- structure(list(eng = c("bathroom", "bedroom", "dining room",
"door", "house", "kitchen", "garden", "neighbor", "office", "attic",
"living room"), nl = c("de badkamer", "de slaapkamer", "de eetkamer",
"de deur", "het huis", "de keuken", "de tuin", "de buurman",
"het kantoor", "de zolder", "de woonkamer")), row.names = c(NA,
-11L), class = "data.frame")
for(i in seq_along(words_lst)){
quiz(caption = paste0(i),
question_text(paste0("Translate: ", words_lst[i,1L]),
answer("C0rrect ", message = "Make sure you do not have a trailing space"),
answer(trimws(words_lst[i, 2L]), correct = TRUE),
incorrect = paste0("Gebruik: ", sub("\\s.*", "", words_lst[i,2L])),
allow_retry = TRUE,
trim = TRUE,
placeholder = "schrijf het juist antwoord"
))
}
```
---
标题:“
输出:learnr::tutorial
运行时:预渲染
说明:“”
---
```{r设置,include=FALSE}
knitr::opts_chunk$set(echo=FALSE)
图书馆(learnr)
```
```{r,q-part2,echo=FALSE,results='asis'}
words_lst我找到了一个解决方案,结果是在一个块中不可能呈现两个或多个函数quick
我的解决方案是在一个循环中生成多个问题\文本
,将它们存储在列表中
,然后使用eval
调用所有问题作为测验的参数。这就是解决方案:
```{r, q-part1, echo=FALSE, message=FALSE, results="asis"}
words_lst <- structure(list(eng = c("bathroom", "bedroom", "dining room",
"door", "house", "kitchen", "garden", "neighbor", "office", "attic",
"living room"), nl = c("de badkamer", "de slaapkamer", "de eetkamer",
"de deur", "het huis", "de keuken", "de tuin", "de buurman",
"het kantoor", "de zolder", "de woonkamer")), row.names = c(NA,
-11L), class = "data.frame")
for (j in 1:nrow(words_lst)) { list_w[[j]] <- question_text(
paste0("Translate: ", words_lst[j, 1L]),
answer("C0rrect ", message = "Make sure you do not have a trailing space"),
answer(trimws(words_lst[j, 2L]), correct = TRUE),
incorrect = paste0("Gebruik: ", sub("\\s.*", "", words_lst[j, 2L])),
allow_retry = TRUE,
trim = TRUE,
placeholder = "schrijf het juist antwoord" ) }
eval(parse(text = paste0( "quiz(", paste0("list_w[[", 1:nrow(words_lst), "]]", collapse = ', '), ")" )))
```
`{r,q-part1,echo=FALSE,message=FALSE,results=“asis”}
words\u lst我认为您必须删除results='asis'
。但我不确定这个循环是否有效。我尝试过这个,但没有成功。