R-使用ggplot2循环，按列名存储绘图

我有这样一个数据帧：

date_list = seq(ymd('2000-01-01'),ymd('2000-12-31'),by='day')
testframe = data.frame(Date = date_list)
testframe$ABC = rnorm(366)
testframe$DEF = rnorm(366)
testframe$GHI = seq(from = 10, to = 25, length.out = 366)
testframe$JKL = seq(from = 5, to = 45, length.out = 366)

我想自动化我下面正在做的事情。我想根据时间日期绘制2:4的每一列。绘图应以p_columnname等格式保存

p_ABC = ggplot(data = testframe, aes(x = Date, y = ABC)) + 
  geom_line(color = "grey", size = 1) 

p_DEF = ggplot(data = testframe, aes(x = Date, y = DEF)) + 
  geom_line(color = "grey", size = 1) 

p_GHI = ggplot(data = testframe, aes(x = Date, y = GHI)) + 
  geom_line(color = "grey", size = 1) 

p_JKL = ggplot(data = testframe, aes(x = Date, y = JKL)) + 
  geom_line(color = "grey", size = 1) 

我试图创建一个循环：

library(ggplot2)
theme_set(theme_gray()) 
for (i in colnames(testframe[2:ncol(testframe)])) {
  paste("p", i, sep = "_") = ggplot(data = testframe, aes(x = Date, y = i)) + 
    geom_line(color = "grey", size = 1) 
} 

那不行！有什么建议吗？

使用lappy和aes_字符串的组合，我们可以生成绘图列表。然后，如果需要，可以按名称提取列表的每个组件

plot_list <- lapply(names(testframe)[-1], 
                    FUN = function(n) 
                        ggplot(testframe, aes_string("Date", n))+geom_line())

names(plot_list) <- paste0("p_", names(testframe)[-1])

plot_list$p_ABC

---

这可能不是最好的方法，但您可以尝试使用递归

f <- colnames(testframe)
sotc <- function(x){
if(is.na(f[x])){return()} 
else
{ assign(paste0("p_",f[x]),  
 ggplot(testframe,aes_string(f[1],f[x]))+geom_line(),envir = globalenv())}

 sotc(x+1)
  }

 sotc(2)

 p_ABC

f <- colnames(testframe)
sotc <- function(x){
if(is.na(f[x])){return()} 
else
{ assign(paste0("p_",f[x]),  
 ggplot(testframe,aes_string(f[1],f[x]))+geom_line(),envir = globalenv())}

 sotc(x+1)
  }

 sotc(2)

 p_ABC