R 替换变量中的值
我有RR 替换变量中的值,r,dataframe,replace,R,Dataframe,Replace,我有R学校的数据,有94个变量。其中,我在一组变量中选择了3个变量进行分析: schools_set <- data.frame(schools$Schoolname, schools$SchoolGenderID, and School$) schools\u setschools$SchoolGenderID[schools$SchoolGenderID==1]尝试数据。表格方式:) 生成的性别列将不是数字,而是字符类型,因为初始列是字符类型。如果需要数字列,则创建新列: schoo
学校的数据,有94个变量。其中,我在一组变量中选择了3个变量进行分析:
schools_set <- data.frame(schools$Schoolname, schools$SchoolGenderID, and School$)
schools\u setschools$SchoolGenderID[schools$SchoolGenderID==1]尝试数据。表格方式:)
生成的性别列将不是数字,而是字符类型,因为初始列是字符类型。如果需要数字列,则创建新列:
schools [ SchoolGenderID == "Male", "SchoolGenderNo" := 1]
schools [ SchoolGenderID == "Female", "SchoolGenderNo" := 2]
这里有一种方法可以在dplyr
library(tidyverse)
schools_set <- schools %>%
select(Schoolname, SchoolGenderID) %>% # Make your subset
mutate(
school_gender_id = ifelse(SchoolGenderID == 1,
"Male", "Female")
) %>%
mutate(
school_gender_id = as.factor(school_gender_id)
) %>%
arrange(school_gender_id) # Order dataframe
库(tidyverse)
学校(单位)
选择(Schoolname,SchoolGenderID)%>%#生成您的子集
变异(
学校性别id=ifelse(学校性别id=1,
“男”、“女”)
) %>%
变异(
学校性别id=as.factor(学校性别id)
) %>%
安排(学校性别id)#订购数据框
mutate
允许您修改变量并创建新变量。按顺序安排工作。如果顺序不正确,您可以改为执行:arrange(desc(school\u gender\u id))
。%%>%%
是一种称为“管道”的命令,意思是“执行此操作后,继续执行下一个命令”
我推荐本教程:
它是由R的创建者Hadley Wickham编写的。非常完整和有用的R编程介绍。如果您学习tidyverse
或schools$SchoolGenderID=c(“男”、“女”)[schools$SchoolGenderID]
,这两种代码都能很好地工作。您能告诉我,既然列中的所有男性都是向上的,然后女性是向下的,那么我该如何排序吗?就像我们在excel中所做的那样。schools[order(schools$SchoolGenderID,discreating=TRUE),]
您的代码不完整。你能澄清一下你的意思吗?总的来说,这并不完全清楚。请为要使用的人员添加一个.schoolsNo data.table()函数。它是给予error@ImadAhmad如果没有,请更新R,并在代码开头的某个地方添加“library(data.table)”“library(data.table)中的错误:没有名为“data.table”的包”。我下载了。使用库(data.table)加载时,会显示上述消息。@如果没有,则需要安装该软件包。键入install.packages(“data.table”)
并按enter键,然后重新加载包(即键入library(data.table)
并按enter键。也许可以阅读一些有关RI尝试安装.packages(“data.table”)中包的介绍性资料,但它仍然给出错误消息。尽管我尝试使用install.packages(“data.table”),dependencies=TRUE)。
schools = data.table (schools)
schools [ SchoolGenderID == "Male", "SchoolGenderID" := "1"]
schools [ SchoolGenderID == "Female", "SchoolGenderID" := "2"]
schools = schools [order (Schoolname, SchoolGenderID)]
schools [ SchoolGenderID == "Male", "SchoolGenderNo" := 1]
schools [ SchoolGenderID == "Female", "SchoolGenderNo" := 2]
library(tidyverse)
schools_set <- schools %>%
select(Schoolname, SchoolGenderID) %>% # Make your subset
mutate(
school_gender_id = ifelse(SchoolGenderID == 1,
"Male", "Female")
) %>%
mutate(
school_gender_id = as.factor(school_gender_id)
) %>%
arrange(school_gender_id) # Order dataframe