用R?绘制数据帧的子集?
我有一个名为用R?绘制数据帧的子集?,r,syntax,plot,subset,R,Syntax,Plot,Subset,我有一个名为fin的数据帧: str(fin) 'data.frame': 158 obs. of 9 variables: $ Species : chr "TRAT" "TRAT" "TRAT" "WRAT" ... $ Site : chr "BAN" "BEX" "BEX" "BEX" ... $ Year : chr "2011" "2010" "2011" "2012" ... $ FR.CoYear: num 35.7
fin
的数据帧:
str(fin)
'data.frame': 158 obs. of 9 variables:
$ Species : chr "TRAT" "TRAT" "TRAT" "WRAT" ...
$ Site : chr "BAN" "BEX" "BEX" "BEX" ...
$ Year : chr "2011" "2010" "2011" "2012" ...
$ FR.CoYear: num 35.7 123.6 136.4 215.8 145.2 ...
$ Sample : int 31 NA 929 809 NA NA NA 30 215 NA ...
$ Young : num 16 NA 828 709 NA NA NA 45 235 NA ...
$ SiteYear : Factor w/ 65 levels "BAN 2011","BAN 2012",..: 1 4 5 6 7 1
我想针对$species
中的5种物种分别绘制FR.CoYear
(fin$Young/fin$Sample)
我尝试了建议的方法;但是目前没有一个可以工作,我非常感谢您的指导-这只是一个语法问题吗
这就是我尝试过的:
with(subset(fin,fin$Species == "TRAT"), plot(fin$FR.CoYear, fin$Young /fin$Sample))
## runs without error but no plot is produced
with(fin[fin$Species == "TRAT",], plot((fin$FR.CoYear, fin$Young / fin$Sample))
##gives the error: unexpected ',' in "with(fin[fin$Species == "TRAT",], plot((fin$FR.CoYear,"
plot(fin$FR.CoYear[fin$Species == "BLKI"],fin$Young / fin$Sample[fin$Species == "BLKI"])
##Error in xy.coords(x, y, xlabel, ylabel, log) :
'x' and 'y' lengths differ
如果这是非常基本的,我很抱歉,但我正在自学R。没有您的数据样本,我无法测试以下答案,但您的代码中有一些错误,我已尝试修复这些错误:
与
或子集一起使用时,您不需要重述名称
当引用单个列时,数据帧的
原始代码:
with(subset(fin,fin$Species == "TRAT"), plot(fin$FR.CoYear, fin$Young /fin$Sample))
改为:
with(subset(fin, Species == "TRAT"), plot(FR.CoYear, Young/Sample))
with(fin[fin$Species == "TRAT",], plot(FR.CoYear, Young / Sample))
plot(fin$FR.CoYear[fin$Species == "BLKI"],
fin$Young[fin$Species == "BLKI"]/ fin$Sample[fin$Species == "BLKI"])
plot
时重述数据帧的名称外,还错放了括号:
原始代码:
with(fin[fin$Species == "TRAT",], plot((fin$FR.CoYear, fin$Young / fin$Sample))
##gives the error: unexpected ',' in "with(fin[fin$Species == "TRAT",], plot((fin$FR.CoYear,"
plot(fin$FR.CoYear[fin$Species == "BLKI"],fin$Young / fin$Sample[fin$Species == "BLKI"])
##Error in xy.coords(x, y, xlabel, ylabel, log) :
'x' and 'y' lengths differ
改为:
with(subset(fin, Species == "TRAT"), plot(FR.CoYear, Young/Sample))
with(fin[fin$Species == "TRAT",], plot(FR.CoYear, Young / Sample))
plot(fin$FR.CoYear[fin$Species == "BLKI"],
fin$Young[fin$Species == "BLKI"]/ fin$Sample[fin$Species == "BLKI"])
fin$Young
还必须按Species
原始代码:
with(fin[fin$Species == "TRAT",], plot((fin$FR.CoYear, fin$Young / fin$Sample))
##gives the error: unexpected ',' in "with(fin[fin$Species == "TRAT",], plot((fin$FR.CoYear,"
plot(fin$FR.CoYear[fin$Species == "BLKI"],fin$Young / fin$Sample[fin$Species == "BLKI"])
##Error in xy.coords(x, y, xlabel, ylabel, log) :
'x' and 'y' lengths differ
改为:
with(subset(fin, Species == "TRAT"), plot(FR.CoYear, Young/Sample))
with(fin[fin$Species == "TRAT",], plot(FR.CoYear, Young / Sample))
plot(fin$FR.CoYear[fin$Species == "BLKI"],
fin$Young[fin$Species == "BLKI"]/ fin$Sample[fin$Species == "BLKI"])
ggplot2
,您可以轻松地为每个物种的价值创建单独的图。例如(再一次,如果没有您的数据样本,我无法对此进行测试):
您可以尝试以下方法:
基本地块,即两个物种:
plot(FR.CoYear ~ Young/Sample, data=subset(fin, Species == "TRAT"))
points(FR.CoYear ~ Young/Sample, col="red",data=subset(fin, Species == "WRAT"))
ggplot(subset(fin, Species %in% c("TRAT", "WRAT")),
aes(x=FR.CoYear,
y=Young/Sample,
color=Species))+
geom_point()
要添加更多物种,只需添加更多点()
ggplot2,即对于两个物种:
plot(FR.CoYear ~ Young/Sample, data=subset(fin, Species == "TRAT"))
points(FR.CoYear ~ Young/Sample, col="red",data=subset(fin, Species == "WRAT"))
ggplot(subset(fin, Species %in% c("TRAT", "WRAT")),
aes(x=FR.CoYear,
y=Young/Sample,
color=Species))+
geom_point()
要在这里添加更多物种,只需添加列表c()上的引用即可
我认为这对您来说是可行的,如果需要,只需测试并更正var名称
向您致以最诚挚的问候以备将来参考,如果您能提供帮助,将更容易为您提供帮助。在本例中,这意味着您的数据样本(除了您已经提供的代码和解释之外)。谢谢您的eipi10,这是一个非常有用的答案,也是ggplot2非常有用的提示。我现在有一些非常好的情节。谢谢