R 在不丢失语料库结构的情况下循环使用tm语料库
我有一个tm文档库和一个单词列表。我想在语料库上运行一个R 在不丢失语料库结构的情况下循环使用tm语料库,r,for-loop,tm,R,For Loop,Tm,我有一个tm文档库和一个单词列表。我想在语料库上运行一个for循环,这样循环就可以按顺序从语料库中删除列表中的每个单词 某些复制数据: library(tm) m <- cbind(c("Apple blue two","Pear yellow five","Banana yellow two"), c(1, 2, 3)) tm_corpus <- Corpus(VectorSource(m[,1])) words <- as.list(c("Appl
for
循环,这样循环就可以按顺序从语料库中删除列表中的每个单词
某些复制数据:
library(tm)
m <- cbind(c("Apple blue two","Pear yellow five","Banana yellow two"),
c(1, 2, 3))
tm_corpus <- Corpus(VectorSource(m[,1]))
words <- as.list(c("Apple", "yellow", "two"))
单词
是由3个单词组成的列表:
[[1]]
[1] "Apple"
[[2]]
[1] "yellow"
[[3]]
[1] "two"
我试过三种不同的循环。第一个是:
tm_corpusClean <- tm_corpus
for (i in seq_along(tm_corpusClean)) {
for (u in seq_along(words)) {
tm_corpusClean[i] <- tm_map(tm_corpusClean[i], removeWords, words[[u]])
}
}
最后一个循环是:
tm_corpusClean <- tm_corpus
for (i in seq_along(words)) {
tm_corpusClean <- tm_map(tm_corpusClean, removeWords, words[[i]])
}
我哪里出错了?在我们开始顺序删除之前,请测试
tm\u map
是否适用于您的示例:
obj1 <- tm_map(tm_corpus, removeWords, unlist(words))
sapply(obj1, `[`, "content")
$`1.content`
[1] " blue "
$`2.content`
[1] "Pear five"
$`3.content`
[1] "Banana "
请注意,生成的语料库位于嵌套列表中(使用两个sappy查看内容的原因)。Hi Adam,感谢您的回答。您的代码可以工作,但给我的是NA,而不是您在此处显示的输出:
obj1obj1[[1]]$content
返回[1]“blue”
,因此NA只在运行sapply(obj1,
[,“content”)
后出现,并给出[1]NA-NA-NA
。但它似乎对语料库本身起了作用。:)这很奇怪。`[`
应该与$
等效
tm_corpusClean <- tm_corpus
for (i in seq_along(words)) {
for (u in seq_along(tm_corpusClean)) {
tm_corpusClean[u] <- tm_map(tm_corpusClean[u], removeWords, words[[i]])
}
}
Error in x$dmeta[i, , drop = FALSE] : incorrect number of dimensions
tm_corpusClean <- tm_corpus
for (i in seq_along(words)) {
tm_corpusClean <- tm_map(tm_corpusClean, removeWords, words[[i]])
}
inspect(tm_corpusClean[[1]])
<<PlainTextDocument>>
Metadata: 7
Content: chars: 6
blue
obj1 <- tm_map(tm_corpus, removeWords, unlist(words))
sapply(obj1, `[`, "content")
$`1.content`
[1] " blue "
$`2.content`
[1] "Pear five"
$`3.content`
[1] "Banana "
obj2 <- lapply(words, function(word) tm_map(tm_corpus, removeWords, word))
sapply(obj2, function(x) sapply(x, `[`, "content"))
[,1] [,2] [,3]
1.content " blue two" "Apple blue two" "Apple blue "
2.content "Pear yellow five" "Pear five" "Pear yellow five"
3.content "Banana yellow two" "Banana two" "Banana yellow "