regex findall根据开始字符和结束字符检索子字符串_Regex_Python 2.7

regex findall根据开始字符和结束字符检索子字符串

regex python-2.7

regex findall根据开始字符和结束字符检索子字符串,regex,python-2.7,Regex,Python 2.7,我有以下字符串： 6[Sup. 1e+02] 我正在尝试检索一个子字符串，其大小仅为1e+02。变量首先引用上述指定的字符串。下面是我试过的 re.findall(' \d*]', first) 您需要使用以下正则表达式： \b\d+e\+\d+\b 说明： \s+(.*?)\] Match a single character that is a “whitespace character” (ASCII space, tab, line feed, carriage return,

我有以下字符串：

6[Sup. 1e+02]

我正在尝试检索一个子字符串，其大小仅为

1e+02

。变量首先引用上述指定的字符串。下面是我试过的

re.findall(' \d*]', first)

您需要使用以下正则表达式：

\b\d+e\+\d+\b

说明：

\s+(.*?)\]

Match a single character that is a “whitespace character” (ASCII space, tab, line feed, carriage return, vertical tab, form feed) «\s+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the regex below and capture its match into backreference number 1 «(.*?)»
   Match any single character that is NOT a line break character (line feed) «.*?»
      Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
Match the character “]” literally «\]»

```
\b
```
-单词边界
```
\d+
```
-数字，1或更多
```
e
```
-文字
```
e
```
```
\+
```
-文字
```
+
```
```
\d+
```
-数字，1或更多
```
\b
```
-单词边界

看

示例代码：

import re
p = re.compile(ur'\b\d+e\+\d+\b')
test_str = u"6[Sup. 1e+02]"
re.findall(p, test_str)

看

输出：

['1e+02']

演示

正则表达式解释：

\s+(.*?)\]

Match a single character that is a “whitespace character” (ASCII space, tab, line feed, carriage return, vertical tab, form feed) «\s+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the regex below and capture its match into backreference number 1 «(.*?)»
   Match any single character that is NOT a line break character (line feed) «.*?»
      Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
Match the character “]” literally «\]»

@比尔盖茨：它可以更整洁，但你只提供了一个例子。我猜所有这些值都在方括号内，并且它们都位于右括号之前。如果没有，请尝试使用

\b\d+e\+\d+\b

-原始字符串，在构建正则表达式时不必使用双斜杠，

表示Unicode字符串。请查看更多详细信息。之所以选择此解决方案，是因为当字符串中的其他位置存在干扰空格时，以及如果输入字符串中有更多的

[]

而没有数字时，此解决方案也有效<代码>6[Sup.1e+02][lorem ipsum]？OP说：“我有以下字符串：

6[Sup.1e+02]

”