Ruby Rspec：积极和消极案例的干燥共享示例

使用RSpec，我如何编写一组干燥的、可用于正面和负面案例的共享示例

适用于积极案例的共享示例：

shared_examples "group1" do
  it "can view a person's private info" do
    @ability.should be_able_to(:view_private_info, person)
  end
  # also imagine I have many other examples of positive cases here
end

---

如果有与

相反的东西，比如
它应该表现得像
，比如
它不应该表现得像
，那就太好了。我理解示例的文本必须灵活。
您可以这样做：

测试类别：

class Hat
  def goes_on_your_head?
    true
  end

  def is_good_to_eat?
    false
  end

end

class CreamPie
  def goes_on_your_head?
    false
  end

  def is_good_to_eat?
    true
  end

end

示例：

shared_examples "a hat or cream pie" do
  it "#{is_more_like_a_hat? ? "goes" : "doesn't go" } on your head" do
    expect(described_class.new.goes_on_your_head?).to eq(is_more_like_a_hat?)
  end

  it "#{is_more_like_a_hat? ? "isn't" : "is" } good to eat" do
    expect(described_class.new.is_good_to_eat?).to eq(!is_more_like_a_hat?)
  end

end

describe Hat do
  it_behaves_like "a hat or cream pie" do
    let(:is_more_like_a_hat?) { true }
  end
end

describe CreamPie do
  it_behaves_like "a hat or cream pie" do
    let(:is_more_like_a_hat?) { false }
  end
end

我不太可能在实际代码中这样做，因为很难编写可理解的示例描述。相反，我将制作两个共享示例，并将复制提取到方法中：

def should_go_on_your_head(should_or_shouldnt)
  expect(described_class.new.goes_on_your_head?).to eq(should_or_shouldnt)
end

def should_be_good_to_eat(should_or_shouldnt)
  expect(described_class.new.is_good_to_eat?).to eq(should_or_shouldnt)
end

shared_examples "a hat" do
  it "goes on your head" do
    should_go_on_your_head true
  end

  it "isn't good to eat" do
    should_be_good_to_eat false
  end

end

shared_examples "a cream pie" do
  it "doesn't go on your head" do
    should_go_on_your_head false
  end

  it "is good to eat" do
    should_be_good_to_eat true
  end

end

describe Hat do
  it_behaves_like "a hat"
end

describe CreamPie do
  it_behaves_like "a cream pie"
end

当然，我不会提取这些方法，甚至根本不会使用共享示例，除非实际示例足够复杂，足以证明它的合理性。
我已经想了好几个月了。我认为这是不可能的，但也许这是最好的。规格可能很难遵循。