Scala 值id不是securesocial.core.Identity的成员

我试图将SecuSocial模块添加到我的scala Play项目中。但我得到一个错误，如下所示：

value id is not a member of securesocial.core.Identity

In /home/ram/Authentication/app/controllers/Application.scala at line 13.

Application.scala

package controllers

import play.api._
import play.api.mvc._
import securesocial.core.{Identity, Authorization}

trait Authorization {       
      def isAuthorized(user: Identity): Boolean
}

case class WithProvider(provider: String) extends Authorization {
    def isAuthorized(user: Identity) = {
      user.id.providerId == provider // ** I got error in this line **
    }
}



object Application extends Controller with securesocial.core.SecureSocial {


  def index = SecuredAction { implicit request =>
    Ok(views.html.index(request.user))
  }

  def myAction = SecuredAction(WithProvider("twitter")) { implicit request =>
      // do something here
      Ok("You can see this because you logged in using Twitter")
  }

//   // a sample action using the new authorization hook
//   def onlyTwitter = SecuredAction(WithProvider("twitter")) { implicit request =>
// //
// //    Note: If you had a User class and returned an instance of it from UserService, this
// //          is how you would convert Identity to your own class:
// //
// //    request.user match {
// //      case user: User => // do whatever you need with your user class
// //      case _ => // did not get a User instance, should not happen,log error/thow exception
// //    }
//     Ok("You can see this because you logged in using Twitter")
//   }

 def page = UserAwareAction { implicit request =>
    val userName = request.user match {
        case Some(user) => user.fullName
        case _ => "guest"
    }
     Ok("Hello %s".format(userName))
  }

  // you don't want to redirect to the login page for ajax calls so
  // adding a ajaxCall = true will make SecureSocial return a forbidden error
  // instead.
  def ajaxCall = SecuredAction(ajaxCall = true) { implicit request =>
    // return some json
  }  

}

构建.sbt

name := "Authentication"

version := "1.0-SNAPSHOT"

libraryDependencies ++= Seq(
  jdbc,
  anorm,
  cache,
  "com.micronautics" % "securesocial" % "2.2.0" withSources
) 

resolvers += Resolver.url("sbt-plugin-snapshots", url("http://repo.scala-sbt.org/scalasbt/sbt-plugin-releases/"))(Resolver.ivyStylePatterns)    

play.Project.playScalaSettings

---

我猜您正在使用Secure Social的主快照。这意味着，中央回购协议中的任何更改都将在您构建时下载

主快照的最新更改如下：

所以你的代码应该是

case class WithProvider(provider: String) extends Authorization {
  def isAuthorized(user: Identity) = {
    user.identityId.providerId == provider
  }
}

---

我猜您正在使用Secure Social的主快照。这意味着，中央回购协议中的任何更改都将在您构建时下载

主快照的最新更改如下：

所以你的代码应该是

case class WithProvider(provider: String) extends Authorization {
  def isAuthorized(user: Identity) = {
    user.identityId.providerId == provider
  }
}

---

我在问题中添加了build.sbt。我的图书馆依赖关系正确吗？或者想要更改？我不使用Play 2.2.0，但如果该版本的SecureSocial已发布，则您可以继续使用它。但我的假设是，我描述的更改也在2.2.0版本中。所以您必须将

id

更改为

identityId

。我在问题中添加了build.sbt。我的图书馆依赖关系正确吗？或者想要更改？我不使用Play 2.2.0，但如果该版本的SecureSocial已发布，则您可以继续使用它。但我的假设是，我描述的更改也在2.2.0版本中。因此，您必须将

id

更改为

identityId

。