Scala 如何使用传递flink流作为参数的api rest并返回转换后的流

Scala 如何使用传递flink流作为参数的api rest并返回转换后的流,scala,apache-flink,flink-streaming,scala-streams,Scala,Apache Flink,Flink Streaming,Scala Streams,我是阿帕奇·弗林克的新手。我有一个flink scala项目,它使用来自kafka集群的数据,我需要将流结果作为参数传递给使用返回该流的api。这是我的密码 class Testing { def main(args: Array[String]): Unit = {} def streamTest(): Unit = { val env: StreamExecutionEnvironment = StreamExecutionEnvironment.getExecutionEn

我是阿帕奇·弗林克的新手。我有一个flink scala项目,它使用来自kafka集群的数据,我需要将流结果作为参数传递给使用返回该流的api。这是我的密码

class Testing {
  def main(args: Array[String]): Unit = {}
  def streamTest(): Unit = {
    val env: StreamExecutionEnvironment = StreamExecutionEnvironment.getExecutionEnvironment
    val properties = new Properties()
    properties.setProperty("bootstrap.servers", "test1.server.local:9092,test2.server.local:9092,test3.server.local:9092")
    val consumer_test = new FlinkKafkaConsumer[String]("topic_test", new SimpleStringSchema(), properties)
    consumer_test.setStartFromEarliest()
    val stream =  env.addSource(consumer_test).setParallelism(5)
    val api_test = "http://api-test.server.local/test/?msg=%s"
    // Here I need pass stream as parameter to api and return transformed stream
    env.execute()
  }   
}

有什么帮助吗?

您应该使用熟悉的任何http/rest库,然后再使用。

这是我的最终代码。我希望这有帮助

class Testing extends Serializable{
  def main(args: Array[String]): Unit = {}
  def streamTest(): Unit = {
    val env: StreamExecutionEnvironment = StreamExecutionEnvironment.getExecutionEnvironment
    val properties = new Properties()
    properties.setProperty("bootstrap.servers", "test1.server.local:9092,test2.server.local:9092,test3.server.local:9092")
    val consumer_test = new FlinkKafkaConsumer[String]("topic_test", new SimpleStringSchema(), properties)
    consumer_test.setStartFromEarliest()
    val stream =  env.addSource(consumer_test)
    // Here I need pass stream as parameter to api and return transformed stream
    val result = stream.flatMap{
      (str, out: Collector[String]) =>
        val api_test = "http://api-test.server.local/test/?msg=%s"
        out.collect {
          getUrl(api_test.format(URLEncoder.encode(str, "UTF-8")))
        }        
    }    
    env.execute()
  }

  def getUrl(url: String): String = {
    val timeout = 5
    val config = RequestConfig.custom.setConnectTimeout(timeout * 1000).setConnectionRequestTimeout(timeout * 1000).setSocketTimeout(timeout * 1000).build
    val client: CloseableHttpClient = HttpClientBuilder.create.setDefaultRequestConfig(config).build
    val request = new HttpGet(url)
    val response = client.execute(request)
    val entity = response.getEntity
    val get_result = EntityUtils.toString(entity)
    get_result
  }     
}

将流结果作为参数传递是什么意思?您是否只想使用来自流的参数执行对API的请求??也许你可以举个例子??我想OP想做一张地图。stream.map(x->call_api(x))我使用stream.flatMap调用函数来连接带out:Collector[String]变量的api rest。谢谢