Sockets UDP服务器，每次循环后输出加倍

我有一个运行良好的UDP服务器/客户端程序

我将从一个客户机接收到的消息发送回所有连接的客户机，但每次循环后输出加倍。 我想我必须用客户机重置ListArray，但是只有第一条消息才会被发送

有人知道吗？谢谢

UDP服务器

    //Listening on Port 12222
    int servPort = 12222;

    UdpClient client = null;

    //Create a new ListArray for the connected Clients
    ArrayList IPArray = new ArrayList();

    try
    {
        //Create an instance of UdpClient
        client = new UdpClient(servPort);
    }
    catch (SocketException se)
    {
        Console.WriteLine(se.ErrorCode + ": " + se.Message);
        Environment.Exit(se.ErrorCode);
    }

    //Create an new IPEndPoint
    IPEndPoint remoteIPEndPoint = new IPEndPoint(IPAddress.Any, 0);


    //Endless loop
    for (; ; )
    { 
        try
        {
            //Receive a byte array with contents
            byte[] byteBuffer = client.Receive(ref remoteIPEndPoint);

            //Message from Client
            string returnData = Encoding.ASCII.GetString(byteBuffer);

            //Add connected Client IPs to ListArray
            IPArray.Add(remoteIPEndPoint);

            //Send the received Message back to all Clients in the ArrayList
            for (int i = 0; i < IPArray.Count; i++)
            {
                Console.WriteLine("Handling client at " + IPArray[i] + " - " + returnData + " arraylist.Length " + IPArray.Count + "\n");

                Byte[] sendBytes = Encoding.ASCII.GetBytes("Clients Send " + returnData + "\n");
                client.Send(sendBytes, sendBytes.Length, (IPEndPoint)IPArray[i]);
            }

            Console.WriteLine("echoed {0} bytes.", byteBuffer.Length);
        }
        catch (SocketException se)
        {
            Console.WriteLine(se.ErrorCode + ": " + se.Message);
        }
    }
}

UDP服务器：

具有iP地址的阵列会随着来自 客户端，但我只想要客户端发送的最后一条消息

如果这是需求，那么就不需要循环。此外，在没有arraylist帮助的情况下，您可以使用remoteIPEndPoint本身显示各个客户端的详细信息。这是做你想做的事的更整洁的方式

从UDP服务器中删除以下行：

...
       //Send the received Message back to all Clients in the ArrayList
        for (int i = 0; i < IPArray.Count; i++)
        {
            Console.WriteLine("Handling client at " + IPArray[i] + " - " + returnData + " arraylist.Length " + IPArray.Count + "\n");

            Byte[] sendBytes = Encoding.ASCII.GetBytes("Clients Send " + returnData + "\n");
            client.Send(sendBytes, sendBytes.Length, (IPEndPoint)IPArray[i]);
        }
...

它所做的是显示向服务器发送消息的客户端的IP地址和端口号\

---

---

此外，对于网络/套接字编程来说，当前的方式并不是更好的方式。您应该始终使用单独的线程（使用ConnectionQueue将它们限制在池中）来接收每个客户端的消息。使用ConnectionQueue来维护线程顺序（可以对每个新的客户端请求重复使用）。

这是预期的，因为代码正在执行cmd上显示的操作！它将继续接收每个客户端响应的字节。因此，随着列表中项目数量的增加，服务器将多次响应处理客户端。。。消息你的问题不清楚除了这个你想要什么？对不起，我的英语不好。iP地址的数组随着来自客户端的每条消息而增长，但我只想要客户端发送的最后一条消息。

...
       //Send the received Message back to all Clients in the ArrayList
        for (int i = 0; i < IPArray.Count; i++)
        {
            Console.WriteLine("Handling client at " + IPArray[i] + " - " + returnData + " arraylist.Length " + IPArray.Count + "\n");

            Byte[] sendBytes = Encoding.ASCII.GetBytes("Clients Send " + returnData + "\n");
            client.Send(sendBytes, sendBytes.Length, (IPEndPoint)IPArray[i]);
        }
...

//1. Now, you can show the count, but, you can get the indiviudal client detail  
//using the remoteIPEndPoint, there is no need of iterating through the array.
Console.WriteLine("This message was sent from " + remoteIPEndPoint.Address.ToString() +
                             " on their port number " +
                             remoteIPEndPoint.Port.ToString() + " - " + returnData + "\n");

//2. Then send the data back to the individual client without using ArrayList, 
// by passing the client's IPEndPoint in the Send() method.
Byte[] sendBytes = Encoding.ASCII.GetBytes("Clients Send " + returnData + "\n");
client.Send(sendBytes, sendBytes.Length, remoteIPEndPoint);