Spring 如何在基于java的配置类（WebAppInitializer）中编写dispatcher sevlet配置

我正在学习java和spring，是否有人能帮助我如何在基于java的配置类WebAppInializer中编写下面给定的dispatcher servlet配置，这是我努力实现但未能成功的。提前准备好

<mvc:resources mapping="/resources/**" location="/resources/"/>
<mvc:view-controller path="/admin.htm" view-name="admin"/>
<mvc:view-controller path="/services.htm" view-name="services"/>

<!--
Most controllers will use the ControllerClassNameHandlerMapping above, but
for the index controller we are using ParameterizableViewController, so we must
define an explicit mapping for it.
-->

 <!--
 The index controller.
  -->
 <bean name="indexController"
 class="org.springframework.web.servlet.mvc.ParameterizableViewController"
 p:viewName="home"/>
 </beans>

My Initializer.java

试试这个

---

这是给HTTP状态404-/project/Nikhil我是否也需要在inializer.java中更改一些内容？Nikhil thanx帮助我获得有用的信息，现在它可以完美地工作了。

import org.springframework.core.annotation.Order;
import org.springframework.web.servlet.support.AbstractAnnotationConfigDispatcherServletInitializer;


@Order(1)
public class Initializer extends
AbstractAnnotationConfigDispatcherServletInitializer {

@Override
protected Class<?>[] getRootConfigClasses() {
return new Class[] {DatabaseConfig.class };
 }
@Override
protected Class<?>[] getServletConfigClasses() {
return new Class<?>[] { WebAppConfig.class };
 }

 @Override
protected String[] getServletMappings() {
    return new String[] { "/" };
 }

}

@Configuration
@ComponentScan("com.myproject")
@EnableWebMvc
public class WebAppConfig extends WebMvcConfigurerAdapter {

    @Override
    public void addResourceHandlers(ResourceHandlerRegistry registry) {
     registry.addResourceHandler("/resources/**").addResourceLocations("/resources/");
}

public void addViewControllers(ViewControllerRegistry registry) {
    registry.addViewController("/admin.htm").setViewName("admin");
    registry.addViewController("/services.htm").setViewName("services");
  }

@Bean(name = "indexController")
  public ParameterizableViewController indexController(){
    ParameterizableViewController parameterizableViewController = new ParameterizableViewController();
    parameterizableViewController.setViewName("home");
    return parameterizableViewController;
  }

}