将SQL中不同xml元素的xml展平为列
我有以下XML将SQL中不同xml元素的xml展平为列,sql,xml,sqlxml,Sql,Xml,Sqlxml,我有以下XML <creatures> <Animals> <Name>Dog</Name> <Name>Cat</Name> <Name>Monkey</Name> </Animals> <NumLegs> <Legs>4</Legs> <Le
<creatures>
<Animals>
<Name>Dog</Name>
<Name>Cat</Name>
<Name>Monkey</Name>
</Animals>
<NumLegs>
<Legs>4</Legs>
<Legs>4</Legs>
<Legs>2</Legs>
</NumLegs>
</creatures>
如何在SQL中实现这一点?我在这个主题上发现的所有其他问题的XML结构都不同。例如,如果XML的结构如下所示,我相信使用节点在XML中解析它是很简单的
<creatures>
<Animal>
<Name>Dog</Name>
<Legs>4</Legs>
</Animal>
.
.
.
</creatures>
您可以为两个集合中的每一行生成索引,然后在该集合上进行联接:
declare @xml xml
set @xml =
'<creatures>
<Animals>
<Name>Dog</Name>
<Name>Cat</Name>
<Name>Monkey</Name>
</Animals>
<NumLegs>
<Legs>4</Legs>
<Legs>4</Legs>
<Legs>2</Legs>
</NumLegs>
</creatures>'
-- create a table of the animals with an index generated by an identity
declare @animals table(n tinyint not null identity(1, 1), animal nvarchar(50) not null)
insert @animals (animal)
select
a.n.value('.', 'nvarchar(50)')
from
@xml.nodes('/creatures/Animals/Name') a(n)
-- create a table of the leg amounts with an index generated by an identity
declare @legs table(n tinyint not null identity(1, 1), amount tinyint not null)
insert @legs (amount)
select
nl.l.value('.', 'tinyint')
from
@xml.nodes('/creatures/NumLegs/Legs') nl(l)
-- bring together the 2 tables based on the index
select
a.animal, l.amount
from
@animals a
join @legs l
on a.n = l.n
非常感谢。这是非常有帮助的。
declare @xml xml
set @xml =
'<creatures>
<Animals>
<Name>Dog</Name>
<Name>Cat</Name>
<Name>Monkey</Name>
</Animals>
<NumLegs>
<Legs>4</Legs>
<Legs>4</Legs>
<Legs>2</Legs>
</NumLegs>
</creatures>'
-- create a table of the animals with an index generated by an identity
declare @animals table(n tinyint not null identity(1, 1), animal nvarchar(50) not null)
insert @animals (animal)
select
a.n.value('.', 'nvarchar(50)')
from
@xml.nodes('/creatures/Animals/Name') a(n)
-- create a table of the leg amounts with an index generated by an identity
declare @legs table(n tinyint not null identity(1, 1), amount tinyint not null)
insert @legs (amount)
select
nl.l.value('.', 'tinyint')
from
@xml.nodes('/creatures/NumLegs/Legs') nl(l)
-- bring together the 2 tables based on the index
select
a.animal, l.amount
from
@animals a
join @legs l
on a.n = l.n