将列数据拆分为行的SQL查询

我有一个sql表，因为我有两个字段，分别是No和declaration

我需要将该代码的声明显示为：

Code  Declaration 
123   a1 - 2nos 
123   a2 - 230nos 
123   a3 - 5nos

---

我需要将该代码的列数据拆分为行。

对于这种类型的数据拆分，我建议创建一个拆分函数：

create FUNCTION [dbo].[Split](@String varchar(MAX), @Delimiter char(1))       
returns @temptable TABLE (items varchar(MAX))       
as       
begin      
    declare @idx int       
    declare @slice varchar(8000)       

    select @idx = 1       
        if len(@String)<1 or @String is null  return       

    while @idx!= 0       
    begin       
        set @idx = charindex(@Delimiter,@String)       
        if @idx!=0       
            set @slice = left(@String,@idx - 1)       
        else       
            set @slice = @String       

        if(len(@slice)>0)  
            insert into @temptable(Items) values(@slice)       

        set @String = right(@String,len(@String) - @idx)       
        if len(@String) = 0 break       
    end   
return 
end;

这将产生以下结果：

| CODE |  DECLARATION |
-----------------------
|  123 |     a1-2 nos |
|  123 |  a2- 230 nos |
|  123 |    a3 - 5nos |

看

或者，您可以实施类似以下内容的CTE版本：

;with cte (code, DeclarationItem, Declaration) as
(
  select Code,
    cast(left(Declaration, charindex(',',Declaration+',')-1) as varchar(50)) DeclarationItem,
         stuff(Declaration, 1, charindex(',',Declaration+','), '') Declaration
  from yourtable
  union all
  select code,
    cast(left(Declaration, charindex(',',Declaration+',')-1) as varchar(50)) DeclarationItem,
    stuff(Declaration, 1, charindex(',',Declaration+','), '') Declaration
  from cte
  where Declaration > ''
) 
select code, DeclarationItem
from cte

几次以前，我也写过同样的博客

另外，请访问自过去15年以来一直保持相同答案的博客。

试试这个

declare @col1 varchar(100),@CurentSubString varchar(100)

create table #temp
(
    col1 varchar(50)
)

DECLARE CUR   CURSOR
FOR     SELECT  col1
        FROM    your_table
open    CUR

FETCH   next 
FROM    CUR
INTO    @col1

WHILE @@FETCH_STATUS = 0
BEGIN

    WHILE   CHARINDEX (@col1, ';') <> 0
    BEGIN
    SET @CurentSubString    =   SUBSTRING(@col1,1,CHARINDEX (@col1, ';'))
    SET @col1 = SUBSTRING(@col1,CHARINDEX (@col1, ';')+1,len(@col1))

    insert into #temp
    select @CurentSubString
END


IF CHARINDEX (@col1, ';') = 0 and isnull(@col1,'')!= '' 
BEGIN
    INSERT INTO #temp
    SELECT @col1
END


FETCH   next 
FROM    CUR
INTO    @col1

END


select  * 
From    #temp

CLOSE   CUR
DEALLOCATE CUR

---

很乐意帮忙。如果此答案有帮助，请确保通过左侧的复选标记接受。这将有助于未来的访客，您将因接受而获得声誉！：由于您的帮助，我得到了代码声明123 a1-2nos 123 a2-230nos 123 a3-5nos 123 a1-100nos 123 a3-6nos的结果。是否可以对重复项求和，并且我需要将输出显示为代码声明123 a1-102nos 123 a2-230nos 123 a3-11nos@Affan我回答了你的另一个问题，给出了如何解决的答案总价值。请指导我在这篇文章。。。

;with cte (code, DeclarationItem, Declaration) as
(
  select Code,
    cast(left(Declaration, charindex(',',Declaration+',')-1) as varchar(50)) DeclarationItem,
         stuff(Declaration, 1, charindex(',',Declaration+','), '') Declaration
  from yourtable
  union all
  select code,
    cast(left(Declaration, charindex(',',Declaration+',')-1) as varchar(50)) DeclarationItem,
    stuff(Declaration, 1, charindex(',',Declaration+','), '') Declaration
  from cte
  where Declaration > ''
) 
select code, DeclarationItem
from cte

Declare @t Table([Code] int, [Declaration] varchar(32));    
Insert Into @t([Code], [Declaration])
Values(123, 'a1-2 nos, a2- 230 nos, a3 - 5nos')

Select 
    x.[Code]
    ,t.Declaration  
    From
    (
        Select 
        *,
        Cast('<X>'+Replace(t.[Declaration],',','</X><X>')+'</X>' As XML) As record

        From @t t
    )x
    Cross Apply
    ( 
        Select fdata.D.value('.','varchar(50)') As Declaration 
        From x.record.nodes('X') As fdata(D)
    ) t

declare @col1 varchar(100),@CurentSubString varchar(100)

create table #temp
(
    col1 varchar(50)
)

DECLARE CUR   CURSOR
FOR     SELECT  col1
        FROM    your_table
open    CUR

FETCH   next 
FROM    CUR
INTO    @col1

WHILE @@FETCH_STATUS = 0
BEGIN

    WHILE   CHARINDEX (@col1, ';') <> 0
    BEGIN
    SET @CurentSubString    =   SUBSTRING(@col1,1,CHARINDEX (@col1, ';'))
    SET @col1 = SUBSTRING(@col1,CHARINDEX (@col1, ';')+1,len(@col1))

    insert into #temp
    select @CurentSubString
END


IF CHARINDEX (@col1, ';') = 0 and isnull(@col1,'')!= '' 
BEGIN
    INSERT INTO #temp
    SELECT @col1
END


FETCH   next 
FROM    CUR
INTO    @col1

END


select  * 
From    #temp

CLOSE   CUR
DEALLOCATE CUR