Sql 获取数据库中唯一约束和索引的列表

我必须得到一个特定数据库的所有唯一键约束和索引的列表。我正在做这样的事情：

SELECT * FROM sys.sysobjects WHERE type!='u' AND name LIKE <tablename> 

从sys.sysobjects中选择*type！='你叫什么名字

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只是想确认这是正确的方法，还是有更好的方法来做同样的事情？

sys.objects中的唯一约束由类型“UQ”表示

 select name from sys.objects where type='UQ'

获取索引

 select i.name, o.name from sys.indexes i
inner join sys.objects o on i.object_id= o.object_id

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您可以从sys.indexes获取唯一键约束和索引。 具体而言，独特的约束条件：

select * from sys.indexes where is_unique_constraint = 1

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由于唯一约束在封面下作为索引实现，因此您可以直接从sys.indexes获得所有这些信息：

SELECT
  [schema] = OBJECT_SCHEMA_NAME([object_id]),
  [table]  = OBJECT_NAME([object_id]),
  [index]  = name, 
  is_unique_constraint,
  is_unique,
  is_primary_key
FROM sys.indexes
-- WHERE [object_id] = OBJECT_ID('dbo.tablename');

要对所有数据库重复此操作（假定没有针对特定表的筛选器）：

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其他答案没有为我返回完整的列表。此查询用于返回所有非主键或系统表的唯一索引：

select i.name as index_name, o.name as object_name
from sys.indexes i
    join sys.objects o on i.object_id= o.object_id
where (i.is_unique_constraint = 1 OR i.is_unique = 1) 
    and i.is_primary_key = 0 and o.type_desc <> 'SYSTEM_TABLE'

选择i.name作为索引名称，选择o.name作为对象名称
从sys.i
在i.object\u id=o.object\u id上连接sys.objects o
其中（i.is_unique_constraint=1或i.is_unique=1）
i.is_primary_key=0和o.type_desc‘系统表’

我在寻找一个解决方案——找到特定表上的所有唯一索引。 我把这个问题作为一个起点

最后，我整理了自己的脚本，我将在这里与大家分享

这个脚本的优点是它提供了索引的列

所有的荣耀都归于原脚本的作者，链接包含在代码中

--====================================================================================
-- Display SQL Server Index Details – Type, Key Columns, Included Columns
-- https://www.ptr.co.uk/blog/sql-server-display-indexes-their-columns-included-columns
--====================================================================================


--Display all indexes along with key columns, included columns and index type

DECLARE @TempTable AS TABLE (SchemaName VARCHAR(100), 
                             ObjectID INT, 
                             TableName VARCHAR(100), 
                             IndexID INT, 
                             IndexName VARCHAR(100), 
                             ColumnID INT, 
                             column_index_id INT, 
                             ColumnNames  VARCHAR(500), 
                             IncludeColumns  VARCHAR(500), 
                             NumberOfColumns INT, 
                             IndexType  VARCHAR(20),
                             IS_UNIQUE BIT,
                             Is_Primary_Key BIT,
                             Is_Unique_Constraint BIT,
                             LastColRecord INT);

WITH CTE_Indexes (SchemaName, ObjectID, TableName, IndexID, IndexName, 
                  ColumnID, column_index_id, ColumnNames, IncludeColumns, 
                  NumberOfColumns, IndexType, Is_Unique,Is_Primary_Key,Is_Unique_Constraint)
AS
(
SELECT s.name, t.object_id, t.name, i.index_id, i.name, c.column_id, ic.index_column_id,
        CASE ic.is_included_column WHEN 0 THEN CAST(c.name AS VARCHAR(5000)) ELSE '' END, 
        CASE ic.is_included_column WHEN 1 THEN CAST(c.name AS VARCHAR(5000)) ELSE '' END, 
        1, i.type_desc,I.is_unique,i.Is_Primary_Key,i.Is_Unique_Constraint 
    FROM  sys.schemas AS s
        JOIN sys.tables AS t ON s.schema_id = t.schema_id
            JOIN sys.indexes AS i ON i.object_id = t.object_id
                JOIN sys.index_columns AS ic 
                  ON ic.index_id = i.index_id 
                 AND ic.object_id = i.object_id
                    JOIN sys.columns AS c 
                      ON c.column_id = ic.column_id 
                     AND c.object_id = ic.object_id
                     AND ic.index_column_id = 1
UNION ALL
SELECT s.name, t.object_id, t.name, i.index_id, i.name, c.column_id, ic.index_column_id,
        CASE ic.is_included_column WHEN 0 THEN CAST(cte.ColumnNames + ', ' + c.name AS VARCHAR(5000))  
                                          ELSE cte.ColumnNames END, 
        CASE  
            WHEN ic.is_included_column = 1 AND cte.IncludeColumns != '' 
                THEN CAST(cte.IncludeColumns + ', ' + c.name AS VARCHAR(5000))
            WHEN ic.is_included_column =1 AND cte.IncludeColumns = '' 
                THEN CAST(c.name AS VARCHAR(5000)) 
            ELSE '' 
        END,
        cte.NumberOfColumns + 1, i.type_desc,I.is_unique,I.Is_Primary_Key,i.Is_Unique_Constraint 
    FROM  sys.schemas AS s
        JOIN sys.tables AS t ON s.schema_id = t.schema_id
            JOIN sys.indexes AS i ON i.object_id = t.object_id
                JOIN sys.index_columns AS ic 
                  ON ic.index_id = i.index_id 
                 AND ic.object_id = i.object_id
                    JOIN sys.columns AS c 
                      ON c.column_id = ic.column_id 
                     AND c.object_id = ic.object_id 
                    JOIN CTE_Indexes cte 
                      ON cte.Column_index_ID + 1 = ic.index_column_id  
                    --JOIN CTE_Indexes cte ON cte.ColumnID + 1 = ic.index_column_id  
                     AND cte.IndexID = i.index_id AND cte.ObjectID = ic.object_id

)
INSERT INTO  @TempTable 
SELECT *, 
  RANK() OVER (PARTITION BY ObjectID, IndexID ORDER BY NumberOfColumns DESC) AS LastRecord 
  FROM CTE_Indexes AS cte;

SELECT SchemaName, TableName, IndexName, ColumnNames, IncludeColumns, IndexType, Is_Unique,Is_Primary_Key,Is_Unique_Constraint   
  FROM @TempTable
 WHERE LastColRecord = 1
 --WHERE T.object_id=OBJECT_ID('dbo.invoiceSelectedOptionalFees')
 --AND objectid=OBJECT_ID('dbo.accountTransaction')
 AND objectid=OBJECT_ID('dbo.invoiceSelectedOptionalFees')
ORDER BY objectid, TableName, indexid, IndexName

在上面的示例中，我使用了下表：

IF OBJECT_ID('[dbo].[invoiceSelectedOptionalFees]') IS NOT NULL 
DROP TABLE [dbo].[invoiceSelectedOptionalFees] 
GO
CREATE TABLE [dbo].[invoiceSelectedOptionalFees] ( 
[Id]         INT              IDENTITY(1,1)                 NOT NULL,
[invoiceId]  INT                              NOT NULL,
[feeTypeId]  INT                              NOT NULL,
CONSTRAINT   [PK__invoiceS__3214EC0703C8693D]  PRIMARY KEY CLUSTERED    ([Id] asc),
CONSTRAINT   [CK_invoiceSelectedOptionalFees_invoice_feeType]  UNIQUE      NONCLUSTERED ([invoiceId] asc, [feeTypeId] asc),
CONSTRAINT   [FK_invoiceSelectedOptionalFees_invoice]                      FOREIGN KEY ([invoiceId]) REFERENCES [invoice]([invoiceID]),
CONSTRAINT   [FK_invoiceSelectedOptionalFees_feeTypes]                     FOREIGN KEY ([feeTypeId]) REFERENCES [feeTypes]([feeTypeID]))

这给了我以下结果：

@Nav我已经进一步澄清了（标题听起来仍然像是你想要跨数据库的结果-我已经留下了我答案的这一部分，以防将来的读者会这样做）。

IF OBJECT_ID('[dbo].[invoiceSelectedOptionalFees]') IS NOT NULL 
DROP TABLE [dbo].[invoiceSelectedOptionalFees] 
GO
CREATE TABLE [dbo].[invoiceSelectedOptionalFees] ( 
[Id]         INT              IDENTITY(1,1)                 NOT NULL,
[invoiceId]  INT                              NOT NULL,
[feeTypeId]  INT                              NOT NULL,
CONSTRAINT   [PK__invoiceS__3214EC0703C8693D]  PRIMARY KEY CLUSTERED    ([Id] asc),
CONSTRAINT   [CK_invoiceSelectedOptionalFees_invoice_feeType]  UNIQUE      NONCLUSTERED ([invoiceId] asc, [feeTypeId] asc),
CONSTRAINT   [FK_invoiceSelectedOptionalFees_invoice]                      FOREIGN KEY ([invoiceId]) REFERENCES [invoice]([invoiceID]),
CONSTRAINT   [FK_invoiceSelectedOptionalFees_feeTypes]                     FOREIGN KEY ([feeTypeId]) REFERENCES [feeTypes]([feeTypeID]))