Sql Oracle-将行转换为列

Sql Oracle-将行转换为列,sql,oracle,oracle12c,transpose,Sql,Oracle,Oracle12c,Transpose,我想把下面的行转换成列。我在考虑PIVOT,但我不相信我能达到预期的结果 原样: ID_NCM | DESTINATION | START | END 36393 | PE | 01-01-2018 | 10-31-2018 36393 | PE | 11-01-2018 | 12-31-9999 将是: ID_NCM | DESTINATION | CURRENT_START | CURRENT_END | FUTURE_START |

我想把下面的行转换成列。我在考虑PIVOT,但我不相信我能达到预期的结果

原样:

ID_NCM | DESTINATION | START      | END  
36393  | PE          | 01-01-2018 | 10-31-2018
36393  | PE          | 11-01-2018 | 12-31-9999
将是:

ID_NCM | DESTINATION | CURRENT_START | CURRENT_END | FUTURE_START | FUTURE_END
36393  | PE          | 01-01-2018    | 10-31-2018  | 11-01-2018   | 12-31-9999
我是否缺少一些表格结构概念,使用select语句无法实现所需的布局


谢谢。

你可以试试这样的东西-

select id_ncm,
       destination,
       max(decode(myrank, 1, start_date)) current_start,
       max(decode(myrank, 1, end_date)) current_end,
       max(decode(myrank, 2, start_date)) future_start,
       max(decode(myrank, 2, end_date)) future_end
  from (select id_ncm,
               destination,
               start_date,
               end_date,
               rank() over(partition by id_ncm order by start_date, end_date) myrank
          from your_table) v1
 group by id_ncm, destination

您可以直接使用带有
min
max
功能的
按ID\u NCM、DESTINATION
分组,如下所示:

with t(ID_NCM,DESTINATION,"START","END") as
(  
 select 36393,'PE',date'2018-01-01',date'2018-10-31' from dual union all
 select 36393,'PE',date'2018-01-11',date'9999-12-31' from dual 
)
select ID_NCM,DESTINATION,
       min("START") as CURRENT_START,min("END") as CURRENT_END,
       max("START") as FUTURE_START,max("END") as FUTURE_END
  from t
 group by ID_NCM,DESTINATION

ID_NCM  DESTINATION CURRENT_START  CURRENT_END   FUTURE_START  FUTURE_END
------  ----------- -------------  ------------  ------------  -----------
36393       PE       01.01.2018     31.10.2018    11.01.2018   31.12.9999
p.S.
START
END
Oracle
中的保留关键字,因此用双引号将它们括起来

编辑:由于您的最后一条评论,您可以通过添加相关子查询进行更改,如下所示:

with t(ID_NCM,DESTINATION,"START","END",tax_rate) as
(  
 select 36393,'PE',date'2018-01-01',date'2018-10-31',0.06 from dual union all
 select 36393,'PE',date'2018-01-11',date'9999-12-31',0.04 from dual 
)
select ID_NCM,DESTINATION,
       min("START") as CURRENT_START,min("END") as CURRENT_END,
       max("START") as FUTURE_START,max("END") as FUTURE_END,
       (select tax_rate from t where "START"=date'2018-01-01' and "END"=date'2018-10-31') 
                                                                         as current_rate,
       (select tax_rate from t where "START"=date'2018-01-11' and "END"=date'9999-12-31') 
                                                                         as future_rate
  from t
 group by ID_NCM,DESTINATION

ID_NCM  DEST   CURRENT_START  CURRENT_END  FUTURE_START  FUTURE_END CURRENT_RATE FUTURE_RATE
------  ----- -------------  ------------  ------------  ----------- ----------- -----------
36393   PE     01.01.2018     31.10.2018    11.01.2018   31.12.9999     0,06          0,04

我试试看。。。谢谢虽然我已经把第一个例子作为解决方案,但我意识到你的例子要简单得多,在我的例子中,行的数量会大大减少。但有一个问题。如果我在“开始”和“结束”列中添加另一列来表示税率(第一行为6%,第二行为4%),会怎么样。MAX/MIN函数没有多大意义。我们如何克服这一点?谢谢