Sql 使用Json\u查询连接数组值

Sql 使用Json\u查询连接数组值,sql,arrays,sql-server,json-query,open-json,Sql,Arrays,Sql Server,Json Query,Open Json,我在SQLServer数据库中有一个表,它在其中一列中存储JSON。结构如下: 桌上人 | Name | ExtraInfo | |--------|:------------------------------------------:| | Bob | {"Age":"23","Colors":["Red","Blue"]} | | James | {"Age":"26","Colors":["Gre

我在SQLServer数据库中有一个表,它在其中一列中存储JSON。结构如下:

桌上人

| Name   |      ExtraInfo                             |
|--------|:------------------------------------------:|
| Bob    |  {"Age":"23","Colors":["Red","Blue"]}      |
| James  |  {"Age":"26","Colors":["Green","Yellow"]}  |
如果我运行此查询:

select
Json_value(ExtraInfo,'$.Age') as Age,
json_query(ExtraInfo, '$.Colors') as Colors
from Persons
我会得到这样的东西:

| Age |Colors              |
|-----|:-------------------|
| 23  |  ["Red","Blue"]    |
| 26  |  ["Green","Yellow"]|
| Age | Colors       |
|-----|:-------------|
| 23  | Red Blue     |
| 26  | Green Yellow |
但是,我需要将JSON数组的
Colors
属性转换为
nvarchar
列,其中数组的所有值由空格字符连接,如下所示:

| Age |Colors              |
|-----|:-------------------|
| 23  |  ["Red","Blue"]    |
| 26  |  ["Green","Yellow"]|
| Age | Colors       |
|-----|:-------------|
| 23  | Red Blue     |
| 26  | Green Yellow |

是否有任何方法可以组合对
json\u query
的多个调用,或者其他类似的方法在一个SQL查询中实现这一点

一个选项是使用
交叉应用
字符串\u agg()

示例

Declare @YourTable Table ([Name] varchar(50),[ExtraInfo] varchar(50))  Insert Into @YourTable Values 
 ('Bob','{"Age":"23","Colors":["Red","Blue"]}')
,('James','{"Age":"26","Colors":["Green","Yellow"]}')


Select Json_value(ExtraInfo,'$.Age') as Age
      ,B.*
 From @YourTable A
 Cross Apply (
                Select Colors = STRING_AGG( value ,' ')
                 From  OpenJSON(json_query(ExtraInfo, '$.Colors'),'$')
             ) B
返回

Age Colors
23  Red Blue
26  Green Yellow

一个选项是使用
交叉应用
字符串\u agg()

示例

Declare @YourTable Table ([Name] varchar(50),[ExtraInfo] varchar(50))  Insert Into @YourTable Values 
 ('Bob','{"Age":"23","Colors":["Red","Blue"]}')
,('James','{"Age":"26","Colors":["Green","Yellow"]}')


Select Json_value(ExtraInfo,'$.Age') as Age
      ,B.*
 From @YourTable A
 Cross Apply (
                Select Colors = STRING_AGG( value ,' ')
                 From  OpenJSON(json_query(ExtraInfo, '$.Colors'),'$')
             ) B
返回

Age Colors
23  Red Blue
26  Green Yellow