Sql 找到多个重复的列，然后将它们全部列出

我发现数据库记录重复如下：

select s.name, r.name Region, c.name Country
from supplier s
join region r on r.id = s.regionid
join region c on c.id = isnull(r.pid, r.id)
group by s.name, r.name, c.name
having count(s.name) >1 

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将它们全部列出的最佳方法是什么（因此，如果有两个重复项，它将显示两次等等）

最简单的方法是从Find dups查询创建一个内嵌查询，并连接到“without-a-group-by”查询

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最简单的方法是从Find dups查询创建一个内嵌查询，并连接到一个“without-a-group-by”查询

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我认为这应该做到：

with C as (
  select
    s.name,
    r.name Region,
    c.name Country,
    count(*) over (
      partition by s.name, r.name, c.name
    ) as ct
  from supplier s
  join region r on r.id = s.regionid
  join region c on c.id = isnull(r.pid, r.id)
)
  select
    name, Region, Country
  from C
  where ct > 1;

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我认为这应该做到：

with C as (
  select
    s.name,
    r.name Region,
    c.name Country,
    count(*) over (
      partition by s.name, r.name, c.name
    ) as ct
  from supplier s
  join region r on r.id = s.regionid
  join region c on c.id = isnull(r.pid, r.id)
)
  select
    name, Region, Country
  from C
  where ct > 1;