Sql 将多个select语句的结果输出为行

我想知道是否有办法将多个select查询的结果显示为行

如果我有如下选择查询：

SELECT count(*), MAX(created_date) from TABLE1;

SELECT COUNT(*), MAX(created_date) from TABLE2;

我期望的结果是

 +----------+-------------------+
 | Count(*) | MAX(created_date) |
 +----------+-------------------+
 |   234    |     10-may-14     |
 |   847    |     03-Apr-14     |
 +----------+-------------------+

谢谢

您可以使用：

如果要标识每行的源，只需创建另一列：

SELECT 'TABLE1' AS Source, COUNT(*), MAX(created_date) from TABLE1
UNION ALL
SELECT 'TABLE2' AS Source, COUNT(*), MAX(created_date) from TABLE2;

您可以使用：

如果要标识每行的源，只需创建另一列：

SELECT 'TABLE1' AS Source, COUNT(*), MAX(created_date) from TABLE1
UNION ALL
SELECT 'TABLE2' AS Source, COUNT(*), MAX(created_date) from TABLE2;

您可以使用：

如果要标识每行的源，只需创建另一列：

SELECT 'TABLE1' AS Source, COUNT(*), MAX(created_date) from TABLE1
UNION ALL
SELECT 'TABLE2' AS Source, COUNT(*), MAX(created_date) from TABLE2;

您可以使用：

如果要标识每行的源，只需创建另一列：

SELECT 'TABLE1' AS Source, COUNT(*), MAX(created_date) from TABLE1
UNION ALL
SELECT 'TABLE2' AS Source, COUNT(*), MAX(created_date) from TABLE2;