Sql 选择没有重叠时间的每个项目

所以，如果我选择非重叠对象，结果应该是：

Item    |   StartTime           |   EndTime
1       |   2015-08-15 03:00:00 |   2015-08-17 12:00:00
1       |   2015-08-15 07:00:00 |   2015-08-17 18:00:00
1       |   2015-08-18 03:00:00 |   2015-08-20 12:00:00
2       |   2015-08-15 03:00:00 |   2015-08-17 12:00:00
2       |   2015-08-15 07:00:00 |   2015-08-17 18:00:00
2       |   2015-08-19 04:00:00 |   2015-08-20 12:00:00

说明

---

• 首先尝试找到两个范围重叠

  T1的匹配。开始时间8-18到8-20与8-19到8-20重叠。我搞糊涂了。@James一个是
  item1
  另一个是
  item2
  请在RDBMS中加上一个标签。您不可编辑。Tks
  1       |   2015-08-18 03:00:00 |   2015-08-20 12:00:00
  2       |   2015-08-19 04:00:00 |   2015-08-20 12:00:00
  
   SELECT T1.*
   FROM YourTable T1
   LEFT JOIN YourTable T2
     ON (T1.StartTime <= T2.EndTime)  and  (T1.EndTime >= T2.StartTime)
    and T1.item = T2.item
    and T1.StartTime <> T2.StartTime
    and T1.EndTime <> T2.EndTime
   WHERE 
       T2.item IS NULL
  
  | Item |                StartTime |                  EndTime |
  |------|--------------------------|--------------------------|
  |    1 | August, 18 2015 03:00:00 | August, 20 2015 12:00:00 |
  |    2 | August, 19 2015 04:00:00 | August, 20 2015 12:00:00 |