编写一个SQL查询，显示字段'；状态'；每月和每年过滤

我有SQL的基本知识，但在更复杂的查询中需要一些帮助

我想获得每个不同“状态”的总计数，即：“活动”“等待用户信息”|“关闭”|“新建”|“已解决”

下面是我想展示的列/结果： 按年份=2015过滤的票证打开月份，以及每个状态的总计数

[“月份”|“活动”|“等待用户信息”|“关闭”|“新建”|“已解决”]

我希望即使结果为0，也能修复这些列

这是我的桌子

CREATE TABLE [dbo].[Incidents](
[Number] [varchar](50) NULL,
[DateOpened] [datetime] NULL,
[Severity] [varchar](50) NULL,
[Priority] [varchar](50) NULL,
[Status] [varchar](50) NULL
) ON [PRIMARY]

谢谢你的帮助

select month(DateOpened),
       sum(case when status = 'Active' then 1 else 0 end) as [Active],
       sum(case when status = 'Awaiting User Info' then 1 else 0 end) as [Awaiting User Info],
       sum(case when status = 'Closed' then 1 else 0 end) as [Closed],
       sum(case when status = 'New' then 1 else 0 end) as [New],
       sum(case when status = 'Resolved' then 1 else 0 end) as [Resolved]
from incidents
where year(DateOpened) = 2015
group by month(DateOpened)

---

如果您想要所有月份，即使没有特定月份的记录，您也可以根据月份名称的联合列表加入表

您应该尝试使用嵌套的

选择
和
分组方式
COUNT
将确保您同时捕获0值注意字段和表格别名：

    SELECT X.M, A.Act as Active, 
           AUI.Await as Awaiting_User_Info, 
           C.Clo as Closed, N.Ne as New R.Res as Resolved 
    FROM   (SELECT MONTH(DateOpened) as M
            FROM Incidents
            GROUP BY MONTH(DateOpened) ) X
    LEFT JOIN
           (SELECT MONTH(DateOpened) as M, 
                   COUNT(*) AS Act 
            FROM Incidents 
            WHERE Status = 'Active' 
            GROUP BY M) A
    ON X.M = A.M LEFT JOIN 
           (SELECT MONTH(DateOpened) as M, 
                   COUNT(*) AS Await 
            FROM Incidents 
            WHERE Status = 'Awaiting User Info' 
            GROUP BY MONTH) AUI
    ON X.M = AUI.M LEFT JOIN 
           (SELECT MONTH(DateOpened) as M, 
            COUNT(*) AS Clo 
            FROM Incidents 
            WHERE Status = 'Closed' GROUP BY MONTH) C
    ON X.M = C.M  LEFT JOIN 
           (SELECT MONTH(DateOpened) as M, 
                   COUNT(*) AS Ne 
            FROM Incidents 
            WHERE Status = 'New' 
            GROUP BY MONTH) N
    ON X.M = N.M LEFT JOIN  
           (SELECT MONTH(DateOpened) as M, 
                   COUNT(*) AS Res 
            FROM Incidents 
            WHERE Status = 'Resolved' 
            GROUP BY MONTH) N
    ON X.M = R.M

我想，它会帮助你的

SELECT *
FROM (
    SELECT 
      month([DateOpened]) as [month], [Status],
        COUNT(*) as cnt
    FROM [Incidents]
    group by month([DateOpened]) , [Status]
) as s
PIVOT
(
    SUM(cnt)
    FOR [Status] IN ( Active , [Awaiting User Info] , [Closed] , [New] , [Resolved])
)AS pivotname

如果对子查询执行
internaljoin
，则只会获得所有子查询的月份present@juergend我已经编辑了我的回复。现在，所有月份都返回了一个新的子查询，没有条件与其他子查询连接。