将XML导入SQL Server,分成多行
我有一个XML文件,需要将其导入SQL Server数据库。XML文件的构建方式如下:将XML导入SQL Server,分成多行,sql,sql-server,xml,Sql,Sql Server,Xml,我有一个XML文件,需要将其导入SQL Server数据库。XML文件的构建方式如下: <report> <deltagere> <deltager> <number>142555267</number> <date>29-12-2006</date> <name> <name> <from>01-05-2000&
<report>
<deltagere>
<deltager>
<number>142555267</number>
<date>29-12-2006</date>
<name>
<name>
<from>01-05-2000</from>
<to>01-01-2003</to>
<text>foo</text>
</name>
<name>
<from>01-01-2003</from>
<to>29-12-2006</to>
<text>bzz</text>
</name>
</name>
<information>
<deltagertype>person</deltagertype>
<leader>John Smith</leader>
<status>Active</status>
</information>
<role>Responsible</role>
</deltager>
<deltager>
<number>4000134982</number>
<date>05-12-2007</date>
<name>
<name>
<from>07-07-2007</from>
<to>05-12-2007</to>
<text>bar</text>
</name>
</name>
<information>
<deltagertype>person</deltagertype>
<leader>Wolfgang Smith</leader>
<status>Active</status>
</information>
<role>Responsible</role>
</deltager>
...
</deltagere>
</report>
-------------------------------------------------------
| number | dato | nameFrom | nameTo | nameText | deltagertype | ...
| 142555267 | 29-12-2006 | 01-05-2000 | 01-01-2003 | foo | person | ...
| 142555267 | 29-12-2006 | 01-01-2003 | 29-12-2006 | bzz | person | ...
| 4000134982 | 05-12-2007 | 07-07-2007 | 05-12-2007 | bar | person | ...
这给了我这个输出:
| number | dato | nameFrom | nameTo | nameText | deltagertype | ...
| 142555267 | 29-12-2006 | 01-05-2000 | 01-01-2003 | foo | person | ...
| 4000134982 | 05-12-2007 | 07-07-2007 | 05-12-2007 | bar | person | ...
我想为每个名称/名称指定一行。比如说:
<report>
<deltagere>
<deltager>
<number>142555267</number>
<date>29-12-2006</date>
<name>
<name>
<from>01-05-2000</from>
<to>01-01-2003</to>
<text>foo</text>
</name>
<name>
<from>01-01-2003</from>
<to>29-12-2006</to>
<text>bzz</text>
</name>
</name>
<information>
<deltagertype>person</deltagertype>
<leader>John Smith</leader>
<status>Active</status>
</information>
<role>Responsible</role>
</deltager>
<deltager>
<number>4000134982</number>
<date>05-12-2007</date>
<name>
<name>
<from>07-07-2007</from>
<to>05-12-2007</to>
<text>bar</text>
</name>
</name>
<information>
<deltagertype>person</deltagertype>
<leader>Wolfgang Smith</leader>
<status>Active</status>
</information>
<role>Responsible</role>
</deltager>
...
</deltagere>
</report>
-------------------------------------------------------
| number | dato | nameFrom | nameTo | nameText | deltagertype | ...
| 142555267 | 29-12-2006 | 01-05-2000 | 01-01-2003 | foo | person | ...
| 142555267 | 29-12-2006 | 01-01-2003 | 29-12-2006 | bzz | person | ...
| 4000134982 | 05-12-2007 | 07-07-2007 | 05-12-2007 | bar | person | ...
等等
我真的不知道该怎么做。因此,我希望你们中的任何人都能对如何修改我的代码有任何想法,以允许使用此方法或不同的方法解决此问题。尝试此方法-您需要执行第二个
.nodes()
调用来枚举所有
子节点:
SELECT
number = deltagere.value('(number)[1]', 'bigint'),
dato = deltagere.value('(date)[1]', 'varchar(10)'),
-- NEW NEW NEW - read from `XC` pseudo columns to get 1-n names
nameFrom = XC.value('(from)[1]', 'varchar(10)'),
nameTo = XC.value('(to)[1]', 'varchar(10)'),
nameText = XC.value('(text)[1]', 'varchar(30)'),
deltagertype = deltagere.value('(information/deltagertype)[1]', 'varchar(20)'),
leader = deltagere.value('(information/leader)[1]', 'varchar(50)'),
deltagerStatus = deltagere.value('(information/status)[1]', 'varchar(50)'),
deltagerRole = deltagere.value('(role)[1]', 'varchar(50)')
FROM
@XmlFile.nodes('/report/deltagere/deltager') AS XTbl(deltagere)
CROSS APPLY
deltagere.nodes('name/name') AS XT2(XC)
你太棒了。这正是我所需要的。谢谢你也许你能帮我解决另一个问题。如果某些节点没有任何节点,该怎么办。然后插入0行。如果是这种情况,有没有办法只在名称列中写入NULL?