Sql 不同、计数、分组查询疯狂

我试图返回每个学期的考试次数。我可以让计数返回，但无法按项对其进行分组

我尝试了所有方法，最接近的方法是按术语分组，但我的计数仅为=1，这是不对的

这是我现在拥有的。它只返回一个计数，如何按项\u id对其进行分组

SELECT COUNT(*) 
  FROM (SELECT DISTINCT ON(student_id, test_event_id, terf.term_id) student_id  
          FROM report.test_event_result_fact terf 
          JOIN report.growth_measurement_window gw on gw.term_id = terf.term_id 
          JOIN report.term t on t.term_id = terf.term_id 
          JOIN report.test tt on tt.test_id = terf.test_id 
         WHERE terf.partner_id = 98 
           AND growth_event_yn = 't' 
           AND gw.test_window_complete_yn = 't' 
           AND gw.growth_window_type = 'DISTRICT' 
           AND tt.test_type_description = 'SURVEY_WITH_GOALS') as TestEvents

---

在不了解更多设置的情况下，这是我的最佳选择：

select term_id, count(*) AS count_per_term
  from (
    select Distinct on (student_id, test_event_id, terf.term_id)
            terf.term_id, student_id
      from report.test_event_result_fact terf
      join report.growth_measurement_window gw using (term_id)
      join report.term t using (term_id)
      join report.test tt using (term_id)
     where terf.partner_id = 98
        and growth_event_yn = 't'
        and gw.test_window_complete_yn = 't'
        and gw.growth_window_type = 'DISTRICT'
        and tt.test_type_description = 'SURVEY_WITH_GOALS') as TestEvents
  group by 1;

---

在不了解更多设置的情况下，这是我的最佳选择：

select term_id, count(*) AS count_per_term
  from (
    select Distinct on (student_id, test_event_id, terf.term_id)
            terf.term_id, student_id
      from report.test_event_result_fact terf
      join report.growth_measurement_window gw using (term_id)
      join report.term t using (term_id)
      join report.test tt using (term_id)
     where terf.partner_id = 98
        and growth_event_yn = 't'
        and gw.test_window_complete_yn = 't'
        and gw.growth_window_type = 'DISTRICT'
        and tt.test_type_description = 'SURVEY_WITH_GOALS') as TestEvents
  group by 1;

---

一条建议-阅读越容易，每个学期就越有可能获得帮助测试？或者每学期每个学生的测试？提示：摆脱所有不相关的连接，以最简单的形式提出你的问题/问题，那么人们将更有可能帮助你一条建议——阅读越容易，每学期获得帮助测试的可能性越大？或者每个学生每个学期的测试？提示：摆脱所有不相关的连接，以最简单的形式提出你的问题，那么人们会更愿意帮助你