Sql 从CTE问题更新

我正在从cte更新，但出现了此常见错误

无法绑定多部分标识符“t.newfips”。

我知道在其他情况下如何处理此错误，但在这种情况下我不知道如何处理

我的问题

with t as (
select * from FIPSModificationsBEA t1
inner join [BEAtoFIPS] t2
on cast(t1.newfips as varchar) = concat(t2.statefips,t2.CountyFIPS)
)
update [BEAtoFIPS]
set statefips = left(t.oldfips, 2) , countyfips = right(t.oldfips, 3)
from [BEAtoFIPS] t2
where concat(t2.statefips, t2.countyfips) =  t.newfips
go

我通过以下查询检查了查询

with t as (
select * from FIPSModificationsBEA t1
inner join [BEAtoFIPS] t2
on cast(t1.newfips as varchar) = concat(t2.statefips,t2.CountyFIPS)
)
select newfips from t
go

---

这个查询有效。因此，我感到困惑。为什么后者有效，而前者无效？它们在结构上不是基本相同吗？前者有什么问题？

您只需更新cte即可：

with t as (
select * from FIPSModificationsBEA t1
inner join [BEAtoFIPS] t2
on cast(t1.newfips as varchar) = concat(t2.statefips,t2.CountyFIPS)
)
update t
set statefips = left(t.oldfips, 2) , countyfips = right(t.oldfips, 3)
go

否则加入到

cte

with t as (
select * from FIPSModificationsBEA t1
inner join [BEAtoFIPS] t2
on cast(t1.newfips as varchar) = concat(t2.statefips,t2.CountyFIPS)
)
update t2
set statefips = left(t.oldfips, 2) , countyfips = right(t.oldfips, 3)
from [BEAtoFIPS] t2
  inner join t
    on concat(t2.statefips, t2.countyfips) =  t.newfips
go

---

您只需更新cte即可：

with t as (
select * from FIPSModificationsBEA t1
inner join [BEAtoFIPS] t2
on cast(t1.newfips as varchar) = concat(t2.statefips,t2.CountyFIPS)
)
update t
set statefips = left(t.oldfips, 2) , countyfips = right(t.oldfips, 3)
go

否则加入到

cte

with t as (
select * from FIPSModificationsBEA t1
inner join [BEAtoFIPS] t2
on cast(t1.newfips as varchar) = concat(t2.statefips,t2.CountyFIPS)
)
update t2
set statefips = left(t.oldfips, 2) , countyfips = right(t.oldfips, 3)
from [BEAtoFIPS] t2
  inner join t
    on concat(t2.statefips, t2.countyfips) =  t.newfips
go

---

您的

UPDATE

查询没有CTE

t

的

FROM

条目（但是您的

选择

，这就是它工作的原因）

考虑CTE的一种方法类似于只对一个查询可见的临时视图。所以你所拥有的（有点）是这样的：

Create View t (...) 
as 
(
select * from FIPSModificationsBEA t1
inner join [BEAtoFIPS] t2
on cast(t1.newfips as varchar) = concat(t2.statefips,t2.CountyFIPS)
)
go

update [BEAtoFIPS]
set statefips = left(t.oldfips, 2) , countyfips = right(t.oldfips, 3)
from [BEAtoFIPS] t2
where concat(t2.statefips, t2.countyfips) =  t.newfips
go

在本例中可能更明显的是，

t

实际上没有在

UPDATE

查询中的任何地方定义

要修复它，您需要将连接到视图，告诉它如何连接到查询：

update [BEAtoFIPS]
set statefips = left(t.oldfips, 2) , countyfips = right(t.oldfips, 3)
from [BEAtoFIPS] t2
join t
on concat(t2.statefips, t2.countyfips) =  t.newfips
go

---

带有CTE的查询需要看起来完全相同-

连接到CTE，并指定它与查询其余部分的关系。您的
更新
查询没有CTE
t
的
FROM
条目（但您的
选择
条目，这就是它工作的原因）

考虑CTE的一种方法类似于只对一个查询可见的临时视图。所以你所拥有的（有点）是这样的：

Create View t (...) 
as 
(
select * from FIPSModificationsBEA t1
inner join [BEAtoFIPS] t2
on cast(t1.newfips as varchar) = concat(t2.statefips,t2.CountyFIPS)
)
go

update [BEAtoFIPS]
set statefips = left(t.oldfips, 2) , countyfips = right(t.oldfips, 3)
from [BEAtoFIPS] t2
where concat(t2.statefips, t2.countyfips) =  t.newfips
go

在本例中可能更明显的是，
t
实际上没有在
UPDATE
查询中的任何地方定义

要修复它，您需要将
连接到视图，告诉它如何连接到查询：

update [BEAtoFIPS]
set statefips = left(t.oldfips, 2) , countyfips = right(t.oldfips, 3)
from [BEAtoFIPS] t2
join t
on concat(t2.statefips, t2.countyfips) =  t.newfips
go

带有CTE的查询需要看起来完全相同-
加入CTE，并指定它与查询其余部分的关系。
您在更新查询中没有加入CTE，因此未分配
t

试试这个：

WITH tempData AS (
    SELECT * FROM FIPSModificationsBEA t1
    INNER JOIN [BEAtoFIPS] t2
    ON CAST(t1.newfips as varchar) = CONCAT(t2.statefips,t2.CountyFIPS)
)

UPDATE t2
SET statefips = LEFT(t.oldfips, 2), 
    countyfips = right(t.oldfips, 3)
FROM [BEAtoFIPS] AS t2
INNER JOIN tempData AS t
    ON t.newFips = concat(t2.statefips, t2.countyfips)

但是，您完全可以在没有cte的情况下执行此操作：

UPDATE b
SET statefips = LEFT(m.oldfips, 2), 
countyfips = RIGHT(m.oldfips, 3)
FROM [BEAtoFIPS] AS b
INNER JOIN FIPSModificationsBEA AS m
    ON CAST(m.newfips as varchar) = CONCAT(b.statefips,b.CountyFIPS)

您尚未在更新查询中加入CTE，因此未分配
t

试试这个：

WITH tempData AS (
    SELECT * FROM FIPSModificationsBEA t1
    INNER JOIN [BEAtoFIPS] t2
    ON CAST(t1.newfips as varchar) = CONCAT(t2.statefips,t2.CountyFIPS)
)

UPDATE t2
SET statefips = LEFT(t.oldfips, 2), 
    countyfips = right(t.oldfips, 3)
FROM [BEAtoFIPS] AS t2
INNER JOIN tempData AS t
    ON t.newFips = concat(t2.statefips, t2.countyfips)

但是，您完全可以在没有cte的情况下执行此操作：

UPDATE b
SET statefips = LEFT(m.oldfips, 2), 
countyfips = RIGHT(m.oldfips, 3)
FROM [BEAtoFIPS] AS b
INNER JOIN FIPSModificationsBEA AS m
    ON CAST(m.newfips as varchar) = CONCAT(b.statefips,b.CountyFIPS)

-您应该始终为所有
varchar
或
nvarchar
变量/参数提供长度。-您应该始终为所有
varchar
或
nvarchar
变量/参数提供长度。