Sql 具有oracle行数的分区

我在Oracle DB中有一个视图，它如下所示：

id  |  type  |   numrows 
----|--------|----------  
1   |   S    |      2     
2   |   L    |      3     
3   |   S    |      2     
4   |   S    |      2     
5   |   L    |      3     
6   |   S    |      2     
7   |   L    |      3     
8   |   S    |      2     
9   |   L    |      3     
10  |   L    |      3   

其思想是：如果类型为“S”，则随机返回2行，如果类型为“L”，则随机返回3行。 例如：

id  |  type  |   numrows
----|--------|----------  
1   |   S    |      2     
3   |   S    |      2     
2   |   L    |      3     
5   |   L    |      3     
7   |   L    |      3   

---

您应该告诉oracle如何获取3行或2行。IDEA是制作一行：

select id, type, numrows
from
    (select 
       id, 
       type, 
       numrows, 
       row_number() over (partition by type order by type) rnk --fabricated
     from table)
where 
   (type = 'S' and rnk <= 2 )
   or
   (type = 'L' and rnk <= 3 );

---

嗨，迭戈。你试过什么？

select id, type, numrows
from
    (select 
       id, 
       type, 
       numrows, 
       row_number() over (partition by type order by dbms_random.random()) rnk --fabricated
     from table)
where 
   rnk <= numrows;