如何在sql SERVER中将sql查询返回的值拆分为多列?
我有一个函数,在调用时返回以下信息:如何在sql SERVER中将sql查询返回的值拆分为多列?,sql,sql-server,Sql,Sql Server,我有一个函数,在调用时返回以下信息: select * from functionName(null, '1 jan 2016', '30 dec 2016') 输出: pcode PayoutDate 100 2016-02-28 00:00:00:000 100 2016-05-31 00:00:00:000 100 3016-08-31 00:00:00:000 100 301
select * from functionName(null, '1 jan 2016', '30 dec 2016')
输出:
pcode PayoutDate
100 2016-02-28 00:00:00:000
100 2016-05-31 00:00:00:000
100 3016-08-31 00:00:00:000
100 3016-11-30 00:00:00:000
103 2016-02-28 00:00:00:000
103 2016-05-31 00:00:00:000
103 3016-08-31 00:00:00:000
103 3016-11-30 00:00:00:000
我们在2月底、5月底、8月底和11月底向客户付款
因此,我想要实现的是每个月都有自己的日期,如下所示:
pcode May August November
100 2016-05-31 00:00:00:000 3016-08-31 00:00:00:000 3016-11-30 00:00:00:000
103 2016-05-31 00:00:00:000 3016-08-31 00:00:00:000 3016-11-30 00:00:00:000
如何拆分数据集以反映如上所示的情况
我真的不知道如何解决这个问题,任何有想法的人?使用PIVOT
SELECT * FROM
(SELECT pcode, datename(month, PayoutDate) AS Month, PayoutDate FROM yourtable) a
PIVOT
(MIN(PayoutDate) FOR Month IN ([May], [August], [November]))b
输出
pcode May August November
100 2016-05-31T00:00:00Z 3016-08-31T00:00:00Z 3016-11-30T00:00:00Z
103 2016-05-31T00:00:00Z 3016-08-31T00:00:00Z 3016-11-30T00:00:00Z
SQL FIDLE:可以将函数结果输入到临时表中。 此处示例表名称:SOF_Pcode
select distinct pcode , (select P1.PayoutDate from SOF_Pcode P1 where P1.pcode =P.pcode and DATEPART(month,P1.PayoutDate) =5) As May
, (select P1.PayoutDate from SOF_Pcode P1 where P1.pcode =P.pcode and DATEPART(month,P1.PayoutDate) =8) As August
, (select P1.PayoutDate from SOF_Pcode P1 where P1.pcode =P.pcode and DATEPART(month,P1.PayoutDate) =11) As November from SOF_Pcode P