Sql 删除同一表中具有匹配多列的行

使用SQL，我有5列：ssn、lastname、firstname、RF和一个标志字段。我需要浏览这个表，其中4列等于另一行，而该行中标志字段的值等于2050，然后删除该2050记录。

谢谢各位，一旦您在打印中看到它，它看起来相当简单。。非常感谢你的帮助。。。

delete from MyTable m
where flag = 2050
and exists (
    select 1 from MyTable where
    MyTable.ssn = m.ssn 
        and MyTable.lastname=m.lastname 
        and MyTable.firstname=m.firstname 
        and MyTable.RF=m.RF 
        and MyTable.flag <> 2050
)

delete from TableName as tn
where tn.flag = 2050 and
exists (select * from TableName as tn2 where tn.ssn = tn2.ssn
        and tn.lastname = tn2.lastname and tn.firstname = tn2.firstname
        and tn.rf = tn2.rf and tn2.flag <> 2050)

DELETE
     T1
FROM
     My_Table T1
INNER JOIN My_Table T2 ON
     T2.ssn = T1.ssn AND
     T2.last_name = T1.last_name AND
     T2.first_name = T1.first_name AND
     T2.RF_name = T1.RF_name AND
     T2.flag <> T1.flag
WHERE
     T1.flag = 2050

delete from Table1 
 where flag = 2050 
   and exists (select * 
                 from Table2 
                where ssn = Table1.ssn
                  and lastname = Table1.lastname 
                  and firstname = Table1.firstname 
                  and rf = Table1.rf 
                  and flag <> 2050)