Sql 将行值转换为列值

我有一张像下面这样的桌子

select * from table1

id  name    Address
1   John    India
1   John    USA
1   John    Spain
2   Tom UK
2   Tom Ecuador
2   Tom Australia

id   name    Address1   Address2    Address3
1    John     India       USA        Spain
2    Tom       UK       Ecuador      Australia

我希望输出如下所示

select * from table1

id  name    Address
1   John    India
1   John    USA
1   John    Spain
2   Tom UK
2   Tom Ecuador
2   Tom Australia

id   name    Address1   Address2    Address3
1    John     India       USA        Spain
2    Tom       UK       Ecuador      Australia

---

您可以使用

行编号（）

和条件聚合：

select id, name,
       max(case when seqnum = 1 then address end) as address1,
       max(case when seqnum = 2 then address end) as address2,
       max(case when seqnum = 3 then address end) as address3
from (select t.*,
             row_number() over (partition by id, name order by (select null)) as seqnum
      from table1 t
     ) t
group by id, name;

---

. . 我根据标题更改了数据库标记。请标记您真正使用的数据库。谢谢戈登。这对我帮助很大lot@ali在这种情况下，请考虑接受并投票回答这个问题。