SQLite：查找具有特定值的集合

我需要找到马克和玛丽攀登过的山峰

我这样做了，但不起作用：

PEAK (NAME, ELEV, DIFF, MAP, REGION)
CLIMBER (NAME, SEX)
PARTICIPATED (TRIP_ID, NAME)
CLIMBED (TRIP_ID, PEAK, WHEN_CLIMBED)

我还试着做：

        select *
        from participated, climbed
        where participated.name="MARY" or "MARK" and participated.trip_id= climbed.trip_id

我将如何执行此操作？

您可以在中使用

Group By name, peak
Having name="MARY" or "MARK"

或者一个合适的或者

    select *
    from participated
    INNER JOIN  climbed ON participated.trip_id= climbed.trip_id
    where participated.name IN ("MARY" , "MARK") 

---

如果您只想找到两个剪辑的峰值，那么就这样做

    select *
    from participated
    INNER JOIN  climbed ON participated.trip_id= climbed.trip_id
    where participated.name = "MARY" OR  participated.name =  "MARK"

---

如果您只想要峰值，可以执行以下操作：

select peak
from participated
join climbed on participated.trip_id = climbed.trip_id
group by peak
having sum(name='MARY') > 0
   and sum(name='MARK') > 0

---

注意正确的

JOIN

语法的使用。

一式三份：和“不工作”（这是否意味着烟雾从桌面散发？它使服务器崩溃？答案错误1000倍？屏幕上有一条错误消息？）请定义“不工作”你可能想在以后的问题中避免使用这种表达方式。但根据问题的答案，这种方法“不起作用”

select c.peak
from climbed c join
     trip t
     on c.trip_id = t.trip_id
where name in ('MARY', 'MARK')
group by c.peak
having count(distinct name) = 2;