String Lua：特定长度的字符串

将

foo

定义为特定长度的字符串

local data = "here is a string"
local no = 12
foo = string.format("%50s %05d",data,no)
print(foo:len(),string.format("%q",foo))

然而，有没有一个简单的方法可以得到

"                                  here is a string 00012"

我知道，我可以用空格填充字符串

data

"here is a string                                   00012"

while data:len（）<50 do data=data..”结束

将减号添加到格式字符串

%-50s

以将文本向左对齐：

while data:len() < 50 do data = data.." " end

输出：

foo = string.format("%-50s %05d","here is a string", 12)
print(foo:len(), foo)

允许的标志：

56  here is a string                                   00012

---

在格式中添加负号：

%-50s

嗯，很简单。。。thankshow用“-”替换空格？@wsha还有另一种方法：

foo=data。。string.rep（“-”，50-data:len（））。。字符串格式（“%05d”，否）

- : left align result inside field
+ : always prefix with a sign, using + if field positive
0 : left-fill with zeroes rather than spaces
(space) : If positive, put a space where the + would have been
# : Changes the behaviour of various formats, as follows:
  For octal conversion (o), prefixes the number with 0 - if necessary.
  For hex conversion (x), prefixes the number with 0x
  For hex conversion (X), prefixes the number with 0X
  For e, E and f formats, always show the decimal point.
  For g and G format, always show the decimal point, and do not truncate trailing zeroes.
  The option to 'always show the decimal point' would only apply if you had the precision set to 0.