Swift 比较从两个字符串计算的值

两个人参加比赛。将有一个简单、困难和中等的问题

每个难度的分数：

• E:1
• M:3
• H:5

用户将输入两个字符串（A和B），函数应找出更大的分数或平局

func winner(A: String, B: String) -> String {

     var sumA = 0
     var sumB = 0
     var sumhigh = 0

     var checker: Bool = false 
     for i in 0..<(A.count-1) {
         if (erica[i] == "E") {
            sumA += 1
            checker = true
         } else if (A[i] == "M"){
            sumA = sumA + 3
            checker = true
         } else if (A[i] == "H"){
            sumA += 3
            checker = true
         }
     }
     return String(sumA)
}

print(winner(A: "EHH", B: "EME"))

Desired result : A Wins // How to achieve this

func赢家（A:String，B:String）->String{
var sumA=0
var sumB=0
var sumhigh=0
var检查器：Bool=false
对于0..中的i，请检查此项

func phraseValue(sentence: String) -> Int
{
  var count = 0
  for letter in sentence
  {
    if letter == "E"
    {
        count += 1
    }
    else if letter == "M"
    {
        count += 3
    }
    else if letter == "H"
    {
        count += 5
    }
  }
 return count
}

最后

func winner(A: String, B: String) -> String {

     var sumA = 0
     var sumB = 0

     sumA = valuePhrase(sentence: A)
     sumB = valuePhrase(sentence: B)

     if sumA == sumB
     {
        return "tie"
     }
     else if sumA > sumB
     {
        return String(sumA) + "A wins"
     }
     else
     {
        return String(sumB) + "B wins"
     }
}

这将比较两个字符串以确定获胜者

func checkWinner(aString: String, bString: String) -> String {

    // Make lowercase for comparison, so that input case does not matter
    let a = aString.lowercased()
    let b = bString.lowercased()

    // Dictionary of values
    let scoreDict: [Character : Int] = ["e": 1, "m": 3, "h": 5]

    // Score variables to increment
    var aTotal = 0
    var bTotal = 0

    // Calculate scores
    for char in a {
        aTotal += scoreDict[char] ?? 0
    }
    for char in b {
        bTotal += scoreDict[char] ?? 0
    }

    // Calculate winner
    if aTotal == bTotal {
        return "It’s a draw"
    } else {
        return aTotal > bTotal ? "A wins! Score: \(aTotal)" : "B wins! Score: \(bTotal)"
    }
}

// Here is an example in which A wins
print(checkWinner(aString: "ehh", bString: "meh"))

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