Swift 通过UITapgestureRecognitor选择器向函数发送参数参数

我正在用TapGestureRecognitor制作一个具有可变浏览量的应用程序。按下视图时，我当前正在执行此操作

func addView(headline: String) {
    // ...
    let theHeadline = headline
    let tapRecognizer = UITapGestureRecognizer(target: self, action: Selector("handleTap:"))
    // ....
}

但是在我的函数“handleTap”中，我想给它一个额外的参数（而不仅仅是发送方），如下所示

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如何将特定标题（每个视图都是唯一的）作为参数发送到handleTap函数？

不是创建通用UITapGestureRecognitor，而是将其子类化并为标题添加属性：

class MyTapGestureRecognizer: UITapGestureRecognizer {
    var headline: String?
}

然后用它来代替：

override func viewDidLoad() {
    super.viewDidLoad()

    let gestureRecognizer = MyTapGestureRecognizer(target: self, action: "tapped:")
    gestureRecognizer.headline = "Kilroy was here."
    view1.addGestureRecognizer(gestureRecognizer)
}

func tapped(gestureRecognizer: MyTapGestureRecognizer) {
    if let headline = gestureRecognizer.headline {
        // Do fun stuff.
    }
}

---

我试过这个。效果很好。

动作部分已经过时了。也似乎不再工作。操作：选择器（ViewController.tapped（：））函数tapped（GestureRecognitizer:MyTapGestureRecognitizer）{…}

override func viewDidLoad() {
    super.viewDidLoad()

    let gestureRecognizer = MyTapGestureRecognizer(target: self, action: "tapped:")
    gestureRecognizer.headline = "Kilroy was here."
    view1.addGestureRecognizer(gestureRecognizer)
}

func tapped(gestureRecognizer: MyTapGestureRecognizer) {
    if let headline = gestureRecognizer.headline {
        // Do fun stuff.
    }
}