Wpf 将XAML路径适配到视图中

我有以下路径。数据来自某个数据文件：

<Path StrokeThickness="5" Stroke="Black" Fill="Yellow" Data="M 30330.8847248349,-37724.909002528 L 28556.3829935257,-37596.5557453925 28031.7660050946,-38008.0608378072 27746.4689258268,-38895.6687979239 27655.7148993139,-39397.1764657993 27718.5888966473,-39755.4955438608 27628.0246979519,-40621.440862981 28514.7500540091,-41208.8847446069 29093.8320242864,-40459.5872073251 29768.3831435369,-40107.7166927063 30092.4525793664,-39483.6045857995 30784.2658266352,-38627.7070622611 30811.846313938,-38537.1499823241 30358.6906348136,-37734.2759127391 30330.8847248349,-37724.909002528" />

---

我想知道这是什么样子，所以我想用Kaxaml或XamlPad渲染它。是否有一种简单的方法可以调整此路径的大小，使其在屏幕上居中显示？

只需将路径的“拉伸”属性设置为“均匀”，以保持apsect比率，您就可以在KaXaml中看到它了

    <Path Stretch="Uniform" StrokeThickness="5" Stroke="Black" Fill="Yellow" Data="M 30330.8847248349,-37724.909002528 L 28556.3829935257,-37596.5557453925 28031.7660050946,-38008.0608378072 27746.4689258268,-38895.6687979239 27655.7148993139,-39397.1764657993 27718.5888966473,-39755.4955438608 27628.0246979519,-40621.440862981 28514.7500540091,-41208.8847446069 29093.8320242864,-40459.5872073251 29768.3831435369,-40107.7166927063 30092.4525793664,-39483.6045857995 30784.2658266352,-38627.7070622611 30811.846313938,-38537.1499823241 30358.6906348136,-37734.2759127391 30330.8847248349,-37724.909002528" />