Xml 在这个golang代码中可以使用更少的'struct'吗？

给定我无法控制的以下XML：

  <Stuff>
  <SomeData>
    <SomeDataStuff>
      <AccountDetails>
        <Person xsi:nil="true" />
        <Person xsi:nil="true" />
      </AccountDetails>
      <CandidateDetails>
        <Candidate xsi:nil="true" />
        <Candidate xsi:nil="true" />
      </CandidateDetails>
    </SomeDataStuff>
  </SomeData>
  </Stuff>

---

我不担心编组，只担心解编组。实际上，我所需要的只是一个

Person

和

Candidate

数组，而不是嵌套的无意义结构的整个序列。您可以使用选择器，例如：

// replace []string with []Person/[]Candidate
type Stuff struct {
    People     []string `xml:"SomeData>SomeDataStuff>AccountDetails>Person"`
    Candidates []string `xml:"SomeData>SomeDataStuff>CandidateDetails>Candidate"`
}

//编辑后，我更新了示例，以显示编组也可以正常工作

发件人：

// replace []string with []Person/[]Candidate
type Stuff struct {
    People     []string `xml:"SomeData>SomeDataStuff>AccountDetails>Person"`
    Candidates []string `xml:"SomeData>SomeDataStuff>CandidateDetails>Candidate"`
}

* If the XML element contains a sub-element whose name matches
   the prefix of a tag formatted as "a" or "a>b>c", unmarshal
   will descend into the XML structure looking for elements with the
   given names, and will map the innermost elements to that struct
   field. A tag starting with ">" is equivalent to one starting
   with the field name followed by ">".