.net 如何在Linq中执行类似SQL%的操作?
我正在尝试将SQL中的一个过程转换为Linq:.net 如何在Linq中执行类似SQL%的操作?,.net,linq,tsql,linq-to-entities,sql-like,.net,Linq,Tsql,Linq To Entities,Sql Like,我正在尝试将SQL中的一个过程转换为Linq: SELECT O.Id, O.Name as Organization FROM Organizations O JOIN OrganizationsHierarchy OH ON O.Id=OH.OrganizationsId where OH.Hierarchy like '%/12/%' 我最关心的是: where OH.Hierarchy like '%/12/%' 我有一个列存储层次结构,比如/1/3/12/,所以我只使用%/12/%
SELECT O.Id, O.Name as Organization
FROM Organizations O
JOIN OrganizationsHierarchy OH ON O.Id=OH.OrganizationsId
where OH.Hierarchy like '%/12/%'
我最关心的是:
where OH.Hierarchy like '%/12/%'
我有一个列存储层次结构,比如/1/3/12/,所以我只使用%/12/%来搜索它
我的问题是,什么是Linq或.NET等同于使用百分号
.Where(oh => oh.Hierarchy.Contains("/12/"))
您也可以使用
.StartsWith()
或.EndsWith()
我假设您使用的是Linq to SQL*(请参见下面的注释)。如果是,请使用string.Contains、string.StartsWith和string.EndsWith生成使用类SQL运算符的SQL
from o in dc.Organization
join oh in dc.OrganizationsHierarchy on o.Id equals oh.OrganizationsId
where oh.Hierarchy.Contains(@"/12/")
select new { o.Id, o.Name }
或
注意:*=如果您在.Net 3.5中使用ADO.Net实体框架(EF/L2E),请注意它不会执行与Linq到SQL相同的转换。尽管L2S进行了正确的转换,L2E v1(3.5)将转换为t-sql表达式,该表达式将强制对正在查询的表进行完整的表扫描,除非where子句或join筛选器中有其他更好的鉴别器。更新:这在EF/L2E v4(.net 4.0)中是固定的,因此它将像L2S一样生成SQL。如果您使用的是VB.net,那么答案将是“*”。下面是where子句的样子
Where OH.Hierarchy Like '*/12/*'
注意:“*”匹配零个或多个字符 使用以下命令:
from c in dc.Organization
where SqlMethods.Like(c.Hierarchy, "%/12/%")
select *;
indexOf对我也很有用
var result = from c in SampleList
where c.LongName.IndexOf(SearchQuery) >= 0
select c;
试试这个,这个对我很好
from record in context.Organization where record.Hierarchy.Contains(12) select record;
我经常这样做:
from h in OH
where h.Hierarchy.Contains("/12/")
select h
我知道我不使用like语句,但它在后台工作正常。这是否可以转换为具有like语句的查询。使用此类代码
try
{
using (DatosDataContext dtc = new DatosDataContext())
{
var query = from pe in dtc.Personal_Hgo
where SqlMethods.Like(pe.nombre, "%" + txtNombre.Text + "%")
select new
{
pe.numero
,
pe.nombre
};
dgvDatos.DataSource = query.ToList();
}
}
catch (Exception ex)
{
string mensaje = ex.Message;
}
Contains在Linq中使用,就像like在SQL中使用一样
string _search="/12/";
您可以使用Linq编写SQL脚本,如下所示:
var result= Organizations.Join(OrganizationsHierarchy.Where(s=>s.Hierarchy.Contains("/12/")),s=>s.Id,s=>s.OrganizationsId,(org,orgH)=>new {org,orgH});
如果您不匹配数字字符串,最好使用普通大小写:
.Where(oh => oh.Hierarchy.ToUpper().Contains(mySearchString.ToUpper()))
对于像我这样在LINQ中寻找“类似SQL”方法的人,我有一个非常好的方法 在这种情况下,我无法以任何方式更改数据库以更改列排序规则。 所以我必须在我的生命中找到一个方法来做这件事 我使用的是helper方法
SqlFunctions.PatIndex
,其作用类似于真正的类SQL操作符
from o in dc.Organization
join oh in dc.OrganizationsHierarchy on o.Id equals oh.OrganizationsId
where oh.Hierarchy.Contains(@"/12/")
select new { o.Id, o.Name }
首先,我需要列举搜索值中所有可能的变音符号(我刚学过的一个单词),以获得如下结果:
déjà => d[éèêëeÉÈÊËE]j[aàâäAÀÂÄ]
montreal => montr[éèêëeÉÈÊËE][aàâäAÀÂÄ]l
montréal => montr[éèêëeÉÈÊËE][aàâäAÀÂÄ]l
然后以LINQ为例:
因此,为了满足我的需要,我编写了一个助手/扩展方法
public static class SqlServerHelper
{
private static readonly List<KeyValuePair<string, string>> Diacritics = new List<KeyValuePair<string, string>>()
{
new KeyValuePair<string, string>("A", "aàâäAÀÂÄ"),
new KeyValuePair<string, string>("E", "éèêëeÉÈÊËE"),
new KeyValuePair<string, string>("U", "uûüùUÛÜÙ"),
new KeyValuePair<string, string>("C", "cçCÇ"),
new KeyValuePair<string, string>("I", "iîïIÎÏ"),
new KeyValuePair<string, string>("O", "ôöÔÖ"),
new KeyValuePair<string, string>("Y", "YŸÝýyÿ")
};
public static string EnumarateDiacritics(this string stringToDiatritics)
{
if (string.IsNullOrEmpty(stringToDiatritics.Trim()))
return stringToDiatritics;
var diacriticChecked = string.Empty;
foreach (var c in stringToDiatritics.ToCharArray())
{
var diac = Diacritics.FirstOrDefault(o => o.Value.ToCharArray().Contains(c));
if (string.IsNullOrEmpty(diac.Key))
continue;
//Prevent from doing same letter/Diacritic more than one time
if (diacriticChecked.Contains(diac.Key))
continue;
diacriticChecked += diac.Key;
stringToDiatritics = stringToDiatritics.Replace(c.ToString(), "[" + diac.Value + "]");
}
stringToDiatritics = "%" + stringToDiatritics + "%";
return stringToDiatritics;
}
}
公共静态类SqlServerHelper
{
private static readonly List Diacritics=new List()
{
新的KeyValuePair(“A”、“Aá–AÀAÄ”),
新的KeyValuePair(“E”、“E”),
新的KeyValuePair(“U”、“UùùUÛÜÙ”),
新的KeyValuePair(“C”、“CçC椆”),
新的键值对(“I”、“IîïIÎÏ”),
新的KeyValuePair(“O”、“O”),
新的KeyValuePair(“Y”、“YŸÝýYÿ”)
};
公共静态字符串EnumarateDiacritics(此字符串StringToDiaCritics)
{
if(string.IsNullOrEmpty(stringToDiatrics.Trim()))
回归医学;
var diacriticChecked=string.Empty;
foreach(stringtoditalitics.ToCharArray()中的变量c)
{
var diac=Diacritics.FirstOrDefault(o=>o.Value.ToCharArray().Contains(c));
if(string.IsNullOrEmpty(diac.Key))
继续;
//防止重复使用同一字母/变音符号
if(diacriticChecked.Contains(diac.Key))
继续;
diacriticChecked+=语音键;
StringToDiatrics=StringToDiatrics.Replace(c.ToString(),“[”+diac.Value+“]);
}
StringToDiatrics=“%”+StringToDiatrics+“%”;
回归医学;
}
}
如果你们中有人建议增强此方法,我将很高兴听到您的建议。.NET core现在有
EF.函数。如
var isMatch=EF.Functions.Like(stringThatMightMatch,pattern);
太晚了,但我将其组合在一起,以便能够使用类似SQL样式的通配符进行字符串比较:
public static class StringLikeExtensions
{
/// <summary>
/// Tests a string to be Like another string containing SQL Like style wildcards
/// </summary>
/// <param name="value">string to be searched</param>
/// <param name="searchString">the search string containing wildcards</param>
/// <returns>value.Like(searchString)</returns>
/// <example>value.Like("a")</example>
/// <example>value.Like("a%")</example>
/// <example>value.Like("%b")</example>
/// <example>value.Like("a%b")</example>
/// <example>value.Like("a%b%c")</example>
/// <remarks>base author -- Ruard van Elburg from StackOverflow, modifications by dvn</remarks>
/// <remarks>converted to a String extension by sja</remarks>
/// <seealso cref="https://stackoverflow.com/questions/1040380/wildcard-search-for-linq"/>
public static bool Like(this String value, string searchString)
{
bool result = false;
var likeParts = searchString.Split(new char[] { '%' });
for (int i = 0; i < likeParts.Length; i++)
{
if (likeParts[i] == String.Empty)
{
continue; // "a%"
}
if (i == 0)
{
if (likeParts.Length == 1) // "a"
{
result = value.Equals(likeParts[i], StringComparison.OrdinalIgnoreCase);
}
else // "a%" or "a%b"
{
result = value.StartsWith(likeParts[i], StringComparison.OrdinalIgnoreCase);
}
}
else if (i == likeParts.Length - 1) // "a%b" or "%b"
{
result &= value.EndsWith(likeParts[i], StringComparison.OrdinalIgnoreCase);
}
else // "a%b%c"
{
int current = value.IndexOf(likeParts[i], StringComparison.OrdinalIgnoreCase);
int previous = value.IndexOf(likeParts[i - 1], StringComparison.OrdinalIgnoreCase);
result &= previous < current;
}
}
return result;
}
/// <summary>
/// Tests a string containing SQL Like style wildcards to be ReverseLike another string
/// </summary>
/// <param name="value">search string containing wildcards</param>
/// <param name="compareString">string to be compared</param>
/// <returns>value.ReverseLike(compareString)</returns>
/// <example>value.ReverseLike("a")</example>
/// <example>value.ReverseLike("abc")</example>
/// <example>value.ReverseLike("ab")</example>
/// <example>value.ReverseLike("axb")</example>
/// <example>value.ReverseLike("axbyc")</example>
/// <remarks>reversed logic of Like String extension</remarks>
public static bool ReverseLike(this String value, string compareString)
{
bool result = false;
var likeParts = value.Split(new char[] {'%'});
for (int i = 0; i < likeParts.Length; i++)
{
if (likeParts[i] == String.Empty)
{
continue; // "a%"
}
if (i == 0)
{
if (likeParts.Length == 1) // "a"
{
result = compareString.Equals(likeParts[i], StringComparison.OrdinalIgnoreCase);
}
else // "a%" or "a%b"
{
result = compareString.StartsWith(likeParts[i], StringComparison.OrdinalIgnoreCase);
}
}
else if (i == likeParts.Length - 1) // "a%b" or "%b"
{
result &= compareString.EndsWith(likeParts[i], StringComparison.OrdinalIgnoreCase);
}
else // "a%b%c"
{
int current = compareString.IndexOf(likeParts[i], StringComparison.OrdinalIgnoreCase);
int previous = compareString.IndexOf(likeParts[i - 1], StringComparison.OrdinalIgnoreCase);
result &= previous < current;
}
}
return result;
}
}
公共静态类StringLikeExtensions
{
///
///测试一个字符串是否与包含类似SQL样式通配符的另一个字符串相似
///
///要搜索的字符串
///包含通配符的搜索字符串
///value.Like(searchString)
///价值。比如(“a”)
///值。例如(“a%”)
///值。例如(“%b”)
///价值。例如(“a%b”)
///价值。例如(“a%b%c”)
///基本作者——StackOverflow的Ruard van Elburg,dvn修改
///由sja转换为字符串扩展名
///
公共静态bool-Like(此字符串值、字符串搜索字符串)
{
布尔结果=假;
var likeParts=searchString.Split(新字符[]{“%”);
for(int i=0;i public static class SqlServerHelper
{
private static readonly List<KeyValuePair<string, string>> Diacritics = new List<KeyValuePair<string, string>>()
{
new KeyValuePair<string, string>("A", "aàâäAÀÂÄ"),
new KeyValuePair<string, string>("E", "éèêëeÉÈÊËE"),
new KeyValuePair<string, string>("U", "uûüùUÛÜÙ"),
new KeyValuePair<string, string>("C", "cçCÇ"),
new KeyValuePair<string, string>("I", "iîïIÎÏ"),
new KeyValuePair<string, string>("O", "ôöÔÖ"),
new KeyValuePair<string, string>("Y", "YŸÝýyÿ")
};
public static string EnumarateDiacritics(this string stringToDiatritics)
{
if (string.IsNullOrEmpty(stringToDiatritics.Trim()))
return stringToDiatritics;
var diacriticChecked = string.Empty;
foreach (var c in stringToDiatritics.ToCharArray())
{
var diac = Diacritics.FirstOrDefault(o => o.Value.ToCharArray().Contains(c));
if (string.IsNullOrEmpty(diac.Key))
continue;
//Prevent from doing same letter/Diacritic more than one time
if (diacriticChecked.Contains(diac.Key))
continue;
diacriticChecked += diac.Key;
stringToDiatritics = stringToDiatritics.Replace(c.ToString(), "[" + diac.Value + "]");
}
stringToDiatritics = "%" + stringToDiatritics + "%";
return stringToDiatritics;
}
}
System.Data.Linq.SqlClient.SqlMethods.Like("mystring", "%string")
public static class StringLikeExtensions
{
/// <summary>
/// Tests a string to be Like another string containing SQL Like style wildcards
/// </summary>
/// <param name="value">string to be searched</param>
/// <param name="searchString">the search string containing wildcards</param>
/// <returns>value.Like(searchString)</returns>
/// <example>value.Like("a")</example>
/// <example>value.Like("a%")</example>
/// <example>value.Like("%b")</example>
/// <example>value.Like("a%b")</example>
/// <example>value.Like("a%b%c")</example>
/// <remarks>base author -- Ruard van Elburg from StackOverflow, modifications by dvn</remarks>
/// <remarks>converted to a String extension by sja</remarks>
/// <seealso cref="https://stackoverflow.com/questions/1040380/wildcard-search-for-linq"/>
public static bool Like(this String value, string searchString)
{
bool result = false;
var likeParts = searchString.Split(new char[] { '%' });
for (int i = 0; i < likeParts.Length; i++)
{
if (likeParts[i] == String.Empty)
{
continue; // "a%"
}
if (i == 0)
{
if (likeParts.Length == 1) // "a"
{
result = value.Equals(likeParts[i], StringComparison.OrdinalIgnoreCase);
}
else // "a%" or "a%b"
{
result = value.StartsWith(likeParts[i], StringComparison.OrdinalIgnoreCase);
}
}
else if (i == likeParts.Length - 1) // "a%b" or "%b"
{
result &= value.EndsWith(likeParts[i], StringComparison.OrdinalIgnoreCase);
}
else // "a%b%c"
{
int current = value.IndexOf(likeParts[i], StringComparison.OrdinalIgnoreCase);
int previous = value.IndexOf(likeParts[i - 1], StringComparison.OrdinalIgnoreCase);
result &= previous < current;
}
}
return result;
}
/// <summary>
/// Tests a string containing SQL Like style wildcards to be ReverseLike another string
/// </summary>
/// <param name="value">search string containing wildcards</param>
/// <param name="compareString">string to be compared</param>
/// <returns>value.ReverseLike(compareString)</returns>
/// <example>value.ReverseLike("a")</example>
/// <example>value.ReverseLike("abc")</example>
/// <example>value.ReverseLike("ab")</example>
/// <example>value.ReverseLike("axb")</example>
/// <example>value.ReverseLike("axbyc")</example>
/// <remarks>reversed logic of Like String extension</remarks>
public static bool ReverseLike(this String value, string compareString)
{
bool result = false;
var likeParts = value.Split(new char[] {'%'});
for (int i = 0; i < likeParts.Length; i++)
{
if (likeParts[i] == String.Empty)
{
continue; // "a%"
}
if (i == 0)
{
if (likeParts.Length == 1) // "a"
{
result = compareString.Equals(likeParts[i], StringComparison.OrdinalIgnoreCase);
}
else // "a%" or "a%b"
{
result = compareString.StartsWith(likeParts[i], StringComparison.OrdinalIgnoreCase);
}
}
else if (i == likeParts.Length - 1) // "a%b" or "%b"
{
result &= compareString.EndsWith(likeParts[i], StringComparison.OrdinalIgnoreCase);
}
else // "a%b%c"
{
int current = compareString.IndexOf(likeParts[i], StringComparison.OrdinalIgnoreCase);
int previous = compareString.IndexOf(likeParts[i - 1], StringComparison.OrdinalIgnoreCase);
result &= previous < current;
}
}
return result;
}
}