Android 在服务上使用SharedReference时出现问题(服务上不存在getPreferences)
我有一些共享首选项(纬度、经度),我希望从服务访问这些首选项,而这些首选项不是活动的子类 特别是,当我尝试访问getPreferences时,服务上不存在此函数。我的代码贴在下面 我在这里的目标是允许在我的服务中写入这些共享首选项。有什么可以帮助我的建议/例子吗Android 在服务上使用SharedReference时出现问题(服务上不存在getPreferences),android,service,sharedpreferences,Android,Service,Sharedpreferences,我有一些共享首选项(纬度、经度),我希望从服务访问这些首选项,而这些首选项不是活动的子类 特别是,当我尝试访问getPreferences时,服务上不存在此函数。我的代码贴在下面 我在这里的目标是允许在我的服务中写入这些共享首选项。有什么可以帮助我的建议/例子吗 public class MyService extends Service implements Runnable { LocationManager mLocationManager; Location mLoca
public class MyService extends Service implements Runnable {
LocationManager mLocationManager;
Location mLocation;
MyLocationListener mLocationListener;
Location currentLocation = null;
static SharedPreferences settings;
static SharedPreferences.Editor configEditor;
public IBinder onBind(Intent intent) {
return null;
}
public void onCreate() {
settings = this.getPreferences(MODE_WORLD_WRITEABLE);
configEditor = settings.edit();
writeSignalGPS();
}
private void setCurrentLocation(Location loc) {
currentLocation = loc;
}
private void writeSignalGPS() {
Thread thread = new Thread(this);
thread.start();
}
@Override
public void run() {
mLocationManager = (LocationManager)getSystemService(Context.LOCATION_SERVICE);
if (mLocationManager.isProviderEnabled(LocationManager.GPS_PROVIDER)) {
Looper.prepare();
mLocationListener = new MyLocationListener();
mLocationManager.requestLocationUpdates(
LocationManager.GPS_PROVIDER, 1000, 0, mLocationListener);
Looper.loop();
//Looper.myLooper().quit();
} else {
Toast.makeText(getBaseContext(),
getResources().getString(R.string.gps_signal_not_found),
Toast.LENGTH_LONG).show();
}
}
private Handler handler = new Handler() {
@Override
public void handleMessage(Message msg) {
if (currentLocation!=null) {
configEditor.putString("mylatitude", ""+currentLocation.getLatitude());
configEditor.putString("mylongitude", ""+currentLocation.getLongitude());
configEditor.commit();
}
}
};
private class MyLocationListener implements LocationListener {
@Override
public void onLocationChanged(Location loc) {
if (loc != null) {
Toast.makeText(getBaseContext(),
getResources().getString(R.string.gps_signal_found),
Toast.LENGTH_LONG).show();
setCurrentLocation(loc);
handler.sendEmptyMessage(0);
}
}
@Override
public void onProviderDisabled(String provider) {}
@Override
public void onProviderEnabled(String provider) {}
@Override
public void onStatusChanged(String provider, int status, Bundle extras) {}
}
我在
settings=this.getPreferences(MODE\u WORLD\u WRITEABLE)一行中得到错误
如果您的应用程序只使用一个共享引用
,则让所有您的代码通过首选项管理器获取。GetDefaultSharedReferences()
如果您声明共享引用为:
private static final String PREFS_NAME = "UserData";
private static final String PREFS_VALUE1 = "value1";
然后使用以下代码获取值:
SharedPreferences preferences = context.getSharedPreferences(PREFS_NAME, Context.MODE_PRIVATE);
value1 = preferences.getString(PREFS_VALUE1, "0");
同样,您甚至可以将值保存到SharedReferences。在这方面帮助您有点晚了,但我希望这对将来的人有所帮助。 这是你的问题:
public void onCreate() {
settings = this.getPreferences(MODE_WORLD_WRITEABLE);
configEditor = settings.edit();
writeSignalGPS();
}
由于您仅在创建服务时检索共享首选项文件,因此服务永远不会正确更新该文件,因此数据永远不会与应用程序共享。在写入共享首选项或检索任何可能已更改的数据之前,请确保再次检索共享首选项文件(重新加载),例如:
private Handler handler = new Handler() {
@Override
public void handleMessage(Message msg) {
if (currentLocation!=null) {
settings = this.getPreferences(MODE_WORLD_WRITEABLE);
configEditor = settings.edit();
configEditor.putString("mylatitude", ""+currentLocation.getLatitude());
configEditor.putString("mylongitude", ""+currentLocation.getLongitude());
configEditor.commit();
}
}
然后在应用程序中:
settings = this.getPreferences(MODE_WORLD_WRITEABLE);
String myLat = setttings.getString("mylatitude","");
此外,Android 3.0上任何服务和活动共享pref的场景,您都应该使用:
settings = this.getPreferences(MODE_MULTI_PROCESS);
实际上,大多数人可能都遇到了这样的问题:在API>=11的设备上,默认情况下,共享首选项不再设置为多进程使用 解决方案:
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.HONEYCOMB) {
prefs = getSharedPreferences(PREFS, 0 | Context.MODE_MULTI_PROCESS);
} else {
prefs = getSharedPreferences(PREFS, 0);
}
对于那些碰上这个的人。。。我也有类似的问题。。。问题的真正原因是我们试图获取/使用未完全初始化的上下文。。我可以在我的IntentService构造函数之外正常使用SharedReference。您能再解释一下我的密码要更改什么才能使用preference manager吗?我正在谷歌上搜索,但我找不到有效的信息me@AndroidUser99:将对
getPreferences()
的调用替换为对PreferenceManager.getDefaultSharedReferences()
@AndroidUser99的调用:问题在于您没有阅读文档@AndroidUser99:更具体地说,GetDefaultSharedReferences()
将上下文
(例如,您的服务
)作为参数。@RuudLenders:IMHO,应用程序本身可能不需要多个SharedReferences
,除非它有自己的多用户概念(与Android在4.2+平板电脑上的多个帐户分开)。但是,库应该使用单独的SharedReferences
,这样它们就不会意外地与包含库的应用程序使用的SharedReferences
发生冲突。根据@Commonware answer上的评论,如何使用PreferenceManager.GetDefaultSharedReferences()做到这一点
?我在一个服务中,不知道默认共享首选项的名称。真的,你救了我。在API 23中,有很多TTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT我的SharedReferences中的某个给定键的值与发送广播意图的活动调用的值不同…重新弃用,看起来我支持使用ContentProvider解决此问题…???哇,真是个救命稻草。