Android SQLite虚拟表ID值不自动递增，返回null

我有一个SQLite虚拟表，我意识到它不是自动递增_id参数，而是重复地将值填充为null

这是我的表格代码

// Chat History Table
    public static String ID = "_id";
    public static String MESSAGE = "message";
    public static String BUSINESS = "business";
    public static String TIMESTAMP = "timestamp";
    public static String FROMTO = "fromto";
    public static String READ = "read";
    public static String LOGGED = "logged";
    public static String AGENT = "agent_id";
    public static String AGENT_NAME = "agent_name";

    // Logging Values
    public static int LOG_SENDING = 2;
    public static int LOG_SENT = 1;
    public static int LOG_FAILED = 0;

    public static final String TABLE_CREATE = "CREATE VIRTUAL TABLE " + TABLE
            + " USING fts3 (" + ID + " INTEGER PRIMARY AUTOINCREMENT, " + READ
            + ", " + BUSINESS + ", " + MESSAGE + ", " + TIMESTAMP + ", "
            + AGENT_NAME + ", " + AGENT + ", " + LOGGED + ", " + FROMTO + ")";

光标的日志消息，用于检查返回的内容

04-16 23:53:17.612:D/MessagingActivity（6313）：时间戳=1397672593064 message=I know\u id=null fromto=0 read=0 logged=null agent\u id=null 代理名称=Aakrit业务=55

---

logged and agent_id为null是设计的，但是id不是

问题在于表示每行唯一标识符的列\u idFTS3表有一个名为rowid的特殊列（它是隐藏的），您应该使用该列而不是\U id列来获取行的标识符

所以你可以试试这个：

select rowid, * from YourTable

现在它应该返回正确的id值，而不是像以前一样为null。这是。 希望它能解决你面临的问题