在android中解析xml数据
我想在android中解析以下数据在android中解析xml数据,android,xml,parsing,Android,Xml,Parsing,我想在android中解析以下数据 <?xml version="1.0" encoding="UTF-8"?> Info: POST /Remindz_api/user/loginHTTP/1.1 Host: www.narola.co Accept: www.narola.co.beepz.api+xml HTTP 1.1 200 OK Content-Type: www.narola.co.beepz.api+xml; Allow : GET,POST
<?xml version="1.0" encoding="UTF-8"?>
Info: POST /Remindz_api/user/loginHTTP/1.1
Host: www.narola.co
Accept: www.narola.co.beepz.api+xml
HTTP 1.1 200 OK
Content-Type: www.narola.co.beepz.api+xml;
Allow : GET,POST
<user id="43">
<firstname>Dfdf</firstname>
<lasttname>p2</lasttname>
<email>p</email>
<telephone>2236</telephone>
<created_on>2013-01-04 04:38:05</created_on>
<atom:link <a href="http://www.narola.co/remindz/reminders/43"></a> />
</user>
感谢advace。使用xml解析技术,如
XmlPullParser
、SAX解析器
或DOM解析器
XML Pull parser是开发者网站推荐的解析器,android是Pull parser的教程 首先,必须从收到的文本块中提取正确的XML 这取决于两种操作:
- 剥离所有与HTTP相关的行
- 修改
public class XMLTest {
static String data = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n" + "\n" + " Info: POST /Remindz_api/user/loginHTTP/1.1\n"
+ " Host: www.narola.co \n" + " Accept: www.narola.co.beepz.api+xml\n" + " HTTP 1.1 200 OK \n"
+ " Content-Type: www.narola.co.beepz.api+xml;\n" + " Allow : GET,POST\n" + "\n" + " <user id=\"43\">\n"
+ " <firstname>Dfdf</firstname>\n" + " <lasttname>p2</lasttname>\n" + " <email>p</email>\n"
+ " <telephone>2236</telephone>\n" + " <created_on>2013-01-04 04:38:05</created_on>\n"
+ " <atom:link <a href=\"http://www.narola.co/remindz/reminders/43\"></a> />\n" + " </user>";
public static void main(final String[] args) {
/*
* This strips off "Param:Value"-style lines
*/
String xmlData = data.replaceAll(" *[a-z\\-A-Z]* *:[^<]*\n", "");
/*
* This strips off "HTTP line"
*/
xmlData = xmlData.replaceAll(" *HTTP .*\n", "");
/*
* Correct atom:link format
*/
xmlData = xmlData.replaceAll("<atom:link (.*) />", "<atom:link>$1</atom:link>");
try {
DocumentBuilder newDocumentBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
Document doc = newDocumentBuilder.parse(new ByteArrayInputStream(xmlData.getBytes("UTF-8")));
Element elem = doc.getDocumentElement();
dump("", elem);
}
catch (Exception e) {
e.printStackTrace();
}
}
public static void dump(final String pad, final Node node)
{
System.out.println(pad + node.toString());
if(node.getChildNodes() != null)
{
for(int i=0; i< node.getChildNodes().getLength();i++)
{
dump(pad + " ", node.getChildNodes().item(i));
}
}
}
公共类XMLTest{
静态字符串数据=“\n”+”\n“+”信息:POST/REMENTZU api/user/loginHTTP/1.1\n”
+“主机:www.narola.co\n”+“接受:www.narola.co.beepz.api+xml\n”+“HTTP 1.1200确定\n”
+内容类型:www.narola.co.beepz.api+xml;\n“+”允许:获取,发布\n“+”\n“+”\n
+“Dfdf\n”+“p2\n”+“p\n”
+“2236\n”+“2013-01-04 04:38:05\n”
+“/>\n”+”;
公共静态void main(最终字符串[]args){
/*
*这将去掉“Param:Value”样式线
*/
字符串xmlData=data.replaceAll(“**[a-z\\-a-z]**:[^只需完成此操作并自行创建。我无法使用此操作分析字符串,因为我的父标记是这样的。然后尝试此操作。它确实有效。您是否尝试过执行XMLTest?生成的XML是有效的XML。解析器可能对根元素和XML声明之间的空格有点挑剔。什么完全不起作用?转储错误的堆栈跟踪我升级了代码,以便有效地处理XML,它是正确的。所有元素都被转储。@Fermando您和我都没有错。请将我的数据作为一个整体,然后应用您的语句它不起作用。它只对您的字符串起作用(由您通过大量连接开发)我不知道为什么它不起作用。
public class XMLTest {
static String data = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n" + "\n" + " Info: POST /Remindz_api/user/loginHTTP/1.1\n"
+ " Host: www.narola.co \n" + " Accept: www.narola.co.beepz.api+xml\n" + " HTTP 1.1 200 OK \n"
+ " Content-Type: www.narola.co.beepz.api+xml;\n" + " Allow : GET,POST\n" + "\n" + " <user id=\"43\">\n"
+ " <firstname>Dfdf</firstname>\n" + " <lasttname>p2</lasttname>\n" + " <email>p</email>\n"
+ " <telephone>2236</telephone>\n" + " <created_on>2013-01-04 04:38:05</created_on>\n"
+ " <atom:link <a href=\"http://www.narola.co/remindz/reminders/43\"></a> />\n" + " </user>";
public static void main(final String[] args) {
/*
* This strips off "Param:Value"-style lines
*/
String xmlData = data.replaceAll(" *[a-z\\-A-Z]* *:[^<]*\n", "");
/*
* This strips off "HTTP line"
*/
xmlData = xmlData.replaceAll(" *HTTP .*\n", "");
/*
* Correct atom:link format
*/
xmlData = xmlData.replaceAll("<atom:link (.*) />", "<atom:link>$1</atom:link>");
try {
DocumentBuilder newDocumentBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
Document doc = newDocumentBuilder.parse(new ByteArrayInputStream(xmlData.getBytes("UTF-8")));
Element elem = doc.getDocumentElement();
dump("", elem);
}
catch (Exception e) {
e.printStackTrace();
}
}
public static void dump(final String pad, final Node node)
{
System.out.println(pad + node.toString());
if(node.getChildNodes() != null)
{
for(int i=0; i< node.getChildNodes().getLength();i++)
{
dump(pad + " ", node.getChildNodes().item(i));
}
}
}
<?xml version="1.0" encoding="UTF-8"?>
<user id="43">
<firstname>Dfdf</firstname>
<lasttname>p2</lasttname>
<email>p</email>
<telephone>2236</telephone>
<created_on>2013-01-04 04:38:05</created_on>
<atom:link><a href="http://www.narola.co/remindz/reminders/43"></a></atom:link>
</user>