Angularjs 如何在量角器中编写检查css类的预期条件？

我有一个id为'public1'的按钮。当我单击该元素时，类状态从ng pristine变为ng dirty：

<input id="public1" class="tile-checkbox ng-valid ng-dirty> Some Text</input>

我会使用：

类似于以下内容（使用ES6 function.includes（）），如果您不想向jasmine添加其他匹配器：

let input = $('#public1');
expect(input.getAttribute('class').then(classes => classes.includes('ng-pristine') && !classes.includes('ng-dirty')).toBeTruthy('Should have "ng-pristine" class ');
input.click();
expect(input.getAttribute('class').then(classes => !classes.includes('ng-pristine') && classes.includes('ng-dirty')).toBeTruthy('Should have "ng-dirty" class after click');

接下来，如果我想通过文本（没有类或属性）找到一个元素，我该怎么做？@KunalOjha在这种情况下，您可以使用xpath:
元素（by.xpath（//input[normalize space（..='Some text']）
。我得到一个错误，提示“toHaveClass（）不是函数”@KunalOjha，它不是内置的匹配器。您必须定义它-请参见答案中的链接线程。谢谢
let input = $('#public1');
expect(input.getAttribute('class').then(classes => classes.includes('ng-pristine') && !classes.includes('ng-dirty')).toBeTruthy('Should have "ng-pristine" class ');
input.click();
expect(input.getAttribute('class').then(classes => !classes.includes('ng-pristine') && classes.includes('ng-dirty')).toBeTruthy('Should have "ng-dirty" class after click');