Arrays 配置单元posexplode用于不均匀值

我有下面的场景

id            date                   issue1    issue2     issue3    issue4     issue5
1   01APR1995~31JAN1992~01JAN1990     0~0~1     1~1~1     0~1~0     1~0~0      0~0~0
2   01APR1996~31JAN1994~01JAN1992     0~0~0     1~0~0     1~1~1      0~0~1     0

下面是我需要的结果

id       date              Issue1   Issue2   Issue3   Issue4    Issue5
1      01JAN1990            1         1       0        0         0             
1      31JAN1992            0         1       1        0         0
1      01APR1995            0         1       0        1         0
2      01JAN1992            0         0       1        1         0
2      31JAN1994            0         0       1        0         null
2      01APR1996            0         1       1        0         null

我尝试了以下代码，但由于某种原因，ID=2只给了我一条记录

select *, row_number() over(partition by  ID order by n1 desc) as seq_num 
from ( 
select id, n1, date,issue1, issue2,issue3, issue4,issue5  
from 
(select * from 
(select distinct 
a.id,
split(a.date,'\\~') c1,
split(a.issue1,'\\~') c2, 
split(a.issue2,'\\~') c3, 
split(a.issue3,'\\~') c4, 
split(a.issue4,'\\~') c5, 
split(a.issue5,'\\~') c6  
from cima_scratch.CLNCL_ASSMT_ANS_DG a) B  
) A 
LATERAL VIEW posexplode(c1) c11 as n1 , date 
LATERAL VIEW posexplode(c2) c22 as n2 , issue1 
LATERAL VIEW posexplode(c3) c33 as n3 , issue2 
LATERAL VIEW posexplode(c4) c44 as n4 , issue3 
LATERAL VIEW posexplode(c5) c55 as n5 , issue4 
LATERAL VIEW posexplode(c6) c66 as n6 , issue5 
where n1=n2 and n1=n3 
and n1 = n4 and n1 = n5 and n1=n6 
) X 

下面是上述代码的结果，其中ID=2有一条记录，而不是3条

id       date              Issue1   Issue2   Issue3   Issue4    Issue5
1      01JAN1990            1         1       0        0         0             
1      31JAN1992            0         1       1        0         0
1      01APR1995            0         1       0        1         0
2      01JAN1992            0         0       1        1         0

---

这里的问题是，多个横向视图用作交叉连接，而where子句仅用于过滤匹配的记录。如果某些侧视图产生的行数较少（id=2的ISSE5包含一个元素），where子句会过滤掉这些行，因为它们与where中的相等条件不匹配。解决方案是在单独的子查询中分解每个数组并使用左联接。这将正常工作，执行得更好，因为不会发生交叉连接。：

with your_data as(--initial data
select stack(2,
1, '01APR1995~31JAN1992~01JAN1990','0~0~1', '1~1~1', '0~1~0', '1~0~0', '0~0~0',
2, '01APR1996~31JAN1994~01JAN1992','0~0~0', '1~0~0', '1~1~1', '0~0~1', '0'
) as (id,dt,issue1,issue2,issue3,issue4,issue5)
),

c11 as(--first array
select  
a.id, c11.n1, c11.dt
from your_data a 
LATERAL VIEW outer posexplode(split(a.dt,'~')) c11 as n1 , dt 
),

c22 as(--second array
select  
a.id, n2, c22.issue1
from your_data a 
LATERAL VIEW outer posexplode(split(a.issue1,'~')) c22 as n2 , issue1 
),

c33 as(--third array
select  
a.id, n3, c33.issue2
from your_data a 
LATERAL VIEW outer posexplode(split(a.issue2,'~')) c33 as n3 , issue2 
),

c44 as(--fourth array
select  
a.id, n4, c44.issue3
from your_data a 
LATERAL VIEW outer posexplode(split(a.issue3,'~')) c44 as n4 , issue3 
),

c55 as(--fifth array
select  
a.id, n5, c55.issue4
from your_data a 
LATERAL VIEW outer posexplode(split(a.issue4,'~')) c55 as n5 , issue4
),

c66 as(--6th array
select  
a.id, n6, c66.issue5
from your_data a 
LATERAL VIEW outer posexplode(split(a.issue5,'~')) c66 as n6 , issue5
)

select c11.id, n1, dt, issue1, issue2, issue3, issue4,issue5
from c11
     left join c22 on c11.id=c22.id and c11.n1=c22.n2
     left join c33 on c11.id=c33.id and c11.n1=c33.n3
     left join c44 on c11.id=c44.id and c11.n1=c44.n4
     left join c55 on c11.id=c55.id and c11.n1=c55.n5
     left join c66 on c11.id=c66.id and c11.n1=c66.n6

结果:

c11.id  n1  dt  issue1  issue2  issue3  issue4  issue5
1   0   01APR1995   0   1   0   1   0
1   1   31JAN1992   0   1   1   0   0
1   2   01JAN1990   1   1   0   0   0
2   0   01APR1996   0   1   1   0   0
2   1   31JAN1994   0   0   1   0   NULL
2   2   01JAN1992   0   0   1   1   NULL

另外，tilde在Java regexp中不是特殊字符，因此不需要使用双斜杠对其进行转义