Assembly 解析器：移动指令上需要的指令

我正在尝试制作一个简单的汇编程序，就是将两个数字相加并显示，然后减去两个数字并显示。但我有一些错误：

oppgave3.asm:28: error: parser: instruction expected
oppgave3.asm:29: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:30: error: symbol `move' redefined
oppgave3.asm:30: error: parser: instruction expected
oppgave3.asm:31: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:32: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:33: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:37: error: symbol `move' redefined
oppgave3.asm:37: error: parser: instruction expected
oppgave3.asm:38: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:39: error: symbol `move' redefined
oppgave3.asm:39: error: parser: instruction expected
oppgave3.asm:40: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:41: error: comma, colon, decorator or end of line expected after operand
oppgave3.asm:42: error: comma, colon, decorator or end of line expected after operand

这就是我要做的：我有两个子程序，一个用于加法，一个用于减法

section .data
a dw 4
b dw 2


section .bss
c resb 1

section .text
global_start:
_start:

call addition
mov eax,4
mov ebx,1
mov ecx,c
mov edx,1
int 0x80

call subtraction
mov eax,4
mov ebx,1
mov ecx,c
mov edx,1
int 0x80

addition:
move eax,[a]
sub eax '0'
move ebx,[b]
sub ebx '0'
add eax and ebx
add eax '0'
mov [c],eax
ret

subtraction:
move eax,[a]
sub eax '0'
move ebx,[b]
sub ebx '0'
sub eax and ebx
add eax '0'
mov [c],eax
ret

你写的是“移动”而不是“移动”

未被识别为指令助记符的标记将被视为标签。Like

move-nop

相当于

move:nop

。这就是为什么在以后的一些使用中会重新定义“

符号“move”

还有其他各种语法错误，比如
sub-eax和ebx
而不是
sub-eax，ebx
，以及
sub-ebx'0'中缺少一个逗号。
我认为您有输入错误。您有一个“move”指令，而我猜它应该是“mov”“最后没有额外的e。我不是组装专家，所以我可能错了。
您希望
添加eax和ebx
做什么-您可能是指
添加eax，ebx
？还有许多其他指令也缺少逗号，例如
sub-eax'0'
，它应该是
sub-eax'0'
。还要注意的是，错误消息非常有用-它们似乎确实在告诉您问题是什么-请尝试更仔细地研究它们。sub ebx“0”应该是
sub ebx，“0”
no？噢！但我仍然得到一个错误，它需要一个逗号、冒号、修饰符或在减法和加法操作数之后的行尾。您有
子eax和ebx
。我不确定你能做到。