C fgets()似乎将输入溢出到其他变量
我正在读取文件,但输入似乎“溢出”到其他变量中 我有两个变量:C fgets()似乎将输入溢出到其他变量,c,fgets,C,Fgets,我正在读取文件,但输入似乎“溢出”到其他变量中 我有两个变量: char str[250]; //used to store input from stream char *getmsg; //already points to some other string 问题是,当我使用fgets()读取输入时 printf("1TOKEN:%s\n",getmsg); fp=fopen("m.txt","r"); fp1=fopen("m1.txt","w");
char str[250]; //used to store input from stream
char *getmsg; //already points to some other string
问题是,当我使用fgets()
读取输入时
printf("1TOKEN:%s\n",getmsg);
fp=fopen("m.txt","r");
fp1=fopen("m1.txt","w");
if(fp!=NULL && fp1!=NULL)
printf("2TOKEN:%s\n",getmsg);
while(fgets(str,250,fp)!=NULL){
printf("3TOKEN:%s\n",getmsg);
printf("read:%s",str);
printf("4TOKEN:%s\n",getmsg);
我得到这样的东西:
1TOKEN:c
2TOKEN:c
3TOKEN:b atob atobbody
read:a b atob atobbody
4TOKEN:b atob atobbody
您可以看到str
是如何流入getmsg
的。那里发生了什么事?我怎样才能避免这种情况发生
提前感谢:)
在代码中,“getmsg”被称为“token”,我认为它可能与相同的名称或其他东西有关,所以我将其更改为getmsg,相同的错误,所以我将其更改回
if(buf[0]=='C'){
int login_error=1;
fp=fopen("r.txt","r");
if(fp!=NULL){
memcpy(&count,&buf[1],2);
pack.boxid=ntohs(count);
memcpy(pack.pword,&buf[3],10);
printf("boxid:%u pword:%s\n",pack.boxid,pack.pword);
while(fgets(str,250,fp)!=NULL){
/*"getmsg"===>*/ token=strtok(str," ");
token=strtok(NULL," ");//receiver uname
token1=strtok(NULL," ");//pword
token2=strtok(NULL," ");//boxid
sscanf(token2,"%hu",&count);//convert char[] to unsigned short
if(pack.boxid==count && strcmp(token1,pack.pword)==0){//uname & pword found
login_error=0;
printf("found:token:%s\n",token);
break;
}
}
if(login_error==1){
count=65535;
pack.boxid=htons(count);
}
if(login_error==0){
count=0;
pack.boxid=htons(count);
}
fclose(fp);
}
printf("1TOKEN:%s\n",token);
if(login_error==0){
int msg_error=1;
fp=fopen("m.txt","r");
fp1=fopen("m1.txt","w");
if(fp!=NULL && fp1!=NULL){
printf("2TOKEN:%s\n",token);
while(fgets(str,250,fp)!=NULL){
printf("3TOKEN:%s\n",token);
printf("read:%s",str);
token1=strtok(str," ");//sender
token2=strtok(NULL," ");//receiver
token3=strtok(NULL," ");//subject
token4=strtok(NULL," ");//body
printf("m.txt:token1:%s token2:%s token3:%s token4:%s\n",token1,token2,token3,token4);
if(msg_error==1 && strcmp(token,token2)==0){//message found
msg_error=0;
count=0;
pack.boxid=htons(count);
strcpy(pack.uname,token1);
strcpy(pack.subject,token3);
strcpy(pack.body,token4);
printf("pack:uname:%s subject:%s body:%s token:%s token2:%s strcmp:%d\n",pack.uname,pack.subject,pack.body,token,token2,strcmp(token,token2));
continue;
}
fprintf(fp1,"%s %s %s %s\n",token1,token2,token3,token4);
}
if(msg_error==1){
count=65534;
pack.boxid=htons(count);
}
printf("count:%u -> boxid:%u\n",count,pack.boxid);
fclose(fp);
fclose(fp1);
}
str[0]='c';
memcpy(&str[1],&pack.boxid,2);
memcpy(&str[3],pack.uname,8);
memcpy(&str[11],pack.subject,20);
memcpy(&str[31],pack.body,200);
str[231]='\0';
bytes=232;
}
}
下面是m.txt,用于存储发送者、接收者、主题和msgbodies:
命名模式非常明显>^
a b atob atobbody
a c atoc atoccc
b c btoc btoccccc
b a btoa btoaaaaa
因此,我试图为接收者“c”获取存储在m.txt中的消息,但它流了过来,非常巧合的是,它返回了“b”的消息….看起来
getmsg
指向了str
缓冲区的第三个字符:
`str` is "a b atob atobbody"
^
|
\__ `getmsg` is pointing there.
因此,每次通过调用
fgets()
更改str
时,getmsg
指向的字符串也会更改,因为它使用相同的内存。您可以发布如何初始化getmsg吗?请发布getmsg init和m.txt,我认为它的标记=strtok(str,”;如果我没记错的话,我记得strtok在str中用“\0”填充分隔符,并将其传递回token。但我不太确定…谢谢你的洞察力!哦。。。我想我现在看到了。。。strtok()似乎解决了这个问题。。。