C 如何循环遍历文件的每一行?
我试图为文件中的每一行分配一个新结构的内存,但当文件为空时,我的循环仍会分配一次内存。问题在于使用while(!feof(file)),但我无法找到while循环的替代检查方法 循环如下所示:C 如何循环遍历文件的每一行?,c,file,C,File,我试图为文件中的每一行分配一个新结构的内存,但当文件为空时,我的循环仍会分配一次内存。问题在于使用while(!feof(file)),但我无法找到while循环的替代检查方法 循环如下所示: while(!feof(f)) { p = (struct PlayerTime*)malloc(sizeof(struct PlayerTime)); head = p; fscanf(f, "%f %s", &p->seconds, p->name);
while(!feof(f))
{
p = (struct PlayerTime*)malloc(sizeof(struct PlayerTime));
head = p;
fscanf(f, "%f %s", &p->seconds, p->name);
p = p->next;
}
// Allocate the space for the first element
struct PlayerTime *head=malloc(sizeof(*head));
// p will always point to a pointer to the element to be filled;
// let's start with the head
struct PlayerTime **p=&head;
// Try to read
while(fscanf(f, "%f %s", &((*p)->seconds), (*p)->name)==2)
{
// If we are here, the last read was successful
// Move p to the pointer to the next element
p = &((*p)->next);
// ... and allocate the space for such element
*p = malloc(sizeof(**p));
}
// After exit, there's an extra element that we allocated but we couldn't read
// Free it
free(*p);
// And put the relevant pointer to NULL
// (it will terminate the list, or set head to NULL if no element has been read)
*p=NULL;
指针和结构都是在循环之前定义的,如果文件中没有任何内容,我就不知道如何让它不循环
feof(f)
表示EOF
尚未命中fscanf
点击EOF
并失败feof(f)
停止循环,因为已命中EOF
while (fscanf(f, "%f %s", &p->seconds, p->name) == 2) {
...
}
提示:还要花更多的时间思考何时以及如何分配内存,可能会发生什么情况,以及应该如何处理这些情况。这一点已经讨论得非常透彻feof
不会告诉您文件是否将在下一次读取时完成,但会告诉您是否已尝试读取但由于文件结束而失败
在您的情况下,解决方案是检查读取是否失败(通过检查fscanf
的返回值),在这种情况下,取消分配结构;这也使您的代码更加健壮,因为它还检查EOF以外的错误(例如IO错误、无效数据格式等)
顺便说一句,p=p->next
不会实现您的期望。如果您正在“动态”构建链接列表,您可以执行以下操作:
while(!feof(f))
{
p = (struct PlayerTime*)malloc(sizeof(struct PlayerTime));
head = p;
fscanf(f, "%f %s", &p->seconds, p->name);
p = p->next;
}
// Allocate the space for the first element
struct PlayerTime *head=malloc(sizeof(*head));
// p will always point to a pointer to the element to be filled;
// let's start with the head
struct PlayerTime **p=&head;
// Try to read
while(fscanf(f, "%f %s", &((*p)->seconds), (*p)->name)==2)
{
// If we are here, the last read was successful
// Move p to the pointer to the next element
p = &((*p)->next);
// ... and allocate the space for such element
*p = malloc(sizeof(**p));
}
// After exit, there's an extra element that we allocated but we couldn't read
// Free it
free(*p);
// And put the relevant pointer to NULL
// (it will terminate the list, or set head to NULL if no element has been read)
*p=NULL;
除了上面的链接,请参见对已接受答案的评论。