输入无效时忽略C scanf

我写了这段代码，它要做的就是输入整数，直到输入负数：

int result = 0, input_number = 0;
while(input_number >= 0){
    printf("Please enter students IDs(negetive to stop)= ");
    result = scanf("%d", &input_number);

    if(result != 1){
        printf("Invalid input! try again...\n");
        continue;
    }
}

当输入为int时，一切正常

但当输入字符时，任何字符都不是int

循环变得无休止，scanf不再请求任何输入

不要建议我使用scanf的替代品，因为这是学校的工作， 必须使用scanf

输入字符输出后：

Please enter students IDs(negetive to stop)= 4
Please enter students IDs(negetive to stop)= 5
Please enter students IDs(negetive to stop)= r
Please enter students IDs(negetive to stop)= Invalid input! try again...
Please enter students IDs(negetive to stop)= Invalid input! try again...
Please enter students IDs(negetive to stop)= Invalid input! try again...
Please enter students IDs(negetive to stop)= Invalid input! try again...
Please enter students IDs(negetive to stop)= Invalid input! try again...
Please enter students IDs(negetive to stop)= Invalid input! try again...
...

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读取字符串，%s是格式说明符，然后在代码中转换为int。如果你是C++，AtoI或Struto就可以工作。 C或C++

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C++

继续；->scanf%*[^\n]；持续马克-我试过了，没有效果；谢谢蓝精灵！工作！