C++ C++；这个while循环有什么问题？

我试图从头开始编写一个简单的文本冒险游戏，作为一个编程练习，结果令人惊讶。以下是完整的代码：

//Twisty Passages All Alike.
//An adventure game designed as a practice exercise.
#include <iostream>
#include <string>
using namespace std;

int main()
{
    cout << "\t\tTwisty Passages, All Alike!\n";
    cout << "\tA text adventure by Jellypox Studios.\n";

    //INVENTORY INDEX NUMBERS:
    //0. note
    //1. hammer
    //2. 


    //ROOM NUMBERS:
    //0. living room
    //1. storeroom


    //Setting up the current room.
    int ALL_ITEMS = 10;
    string inventory[ALL_ITEMS];
    int currentRoom = 0;

    string input = "DEFAULT";

    //Room 0: living room.
    bool haveNote = false;
    bool haveHammer = false;

    //Room descriptions
    if (currentRoom == 0)
    {
        cout << "You are in the living room.\nThere are doors to the south and west and a staircase to the north.\nYou can see: a table, a cat, a fireplace.\n\n";
    }
    else if (currentRoom == 1)
    {
        cout << "You are in the storeroom.\nThe room is a jumbled mass of cupboards, hanging sausages, left-out scraps of food and cockroaches.\nThe only thing of interest here is a large chest in the corner.";
    }


    //THE LIVING ROOM
    while (currentRoom == 0)
    {
        cin >> input;
        //THE TABLE
        if (input == "look table" || "look at table")
        {
            cout << "You see: some bones and scraps";
            if (haveHammer = false)
            {
                cout << ", a hammer";
            }
            if (haveNote == false)
            {
                cout << ", a note";
            }
            cout << ".\n\n";
        }
        else if (input == "look scraps" || "look at scraps" || "look bones" || "look at bones")
        {
            cout << "What a mess!\n\n";
        }
        else if (input == "look note" || "look at note" || "read note")
        {
            if (haveNote == false)
            {
                cout << "Pick it up first!\n\n";
            }
            else
            {
                cout << "It reads: \"Gone hunting. Will be back soon.\"";
            }
        }
        else if (input == "get note" || "take note" || "pick up note")
        {
            if (haveNote == false)
            {
                cout << "Got the note.";
                inventory[0] = "note";
                haveNote = true;
            }
            else
            {
                cout << "You already have the note!\n\n";
            }
        }
        else if (input == "look hammer" || "look at hammer")
        {
            cout << "It's just an ordinary hammer.\n\n";
        }
        else if (input == "get hammer" || "take hammer" || "pick up hammer")
        {
            if (haveHammer == false)
            {
                cout << "Got the hammer.\n\n";
                inventory[1] = "hammer";
                haveHammer = true;
            }
            else
            {
                cout << "You already have the hammer!\n\n";
            }
        }
        //ELSWHERE IN THE ROOM
        else if (input == "look cat" || "look at cat")
        {
            cout << "It stares up at you irritably.\n\n";
        }
        else if (input == "look fireplace" || "look at fireplace")
        {
            cout << "A flickering fire warms the house.\n\n";
        }
        else if (input == "south" || "go south")
        {
            //CODE TO MAKE THE DOOR UNLOCKABLE GOES HERE!
            cout << "The door is locked.\n\n";
        }
        else if (input == "west" || "go west")
        {
            currentRoom = 1;
        }
        else if (input == "north" || "go north" || "upstairs" || "go upstairs")
        {
            currentRoom = 2;
        }
        else
        {
            cout << "Say what?";
        }
    }
    return 0;
}

我到底弄错了什么？

它会为输入的每个单词打印一次“你看：一些骨头…”。如果你输入“敏捷的棕色狐狸跳过了懒惰的狗”，它可能会打印“你看：…”9次。因此，看起来您的“cin>>输入”正在将输入字符串拆分为令牌。你必须弄清楚如何让它读一整行，并把它作为一个字符串交给你；对C++我生疏了，我记不起来了。p> 此外，您还编写了：if（输入=“looktable”| |“looktable”）

---

这里的问题是“看表”总是正确的，所以表达式总是正确的。您可能希望：例如，如果（输入==“look table”| |输入==“look at table”）

这段代码中有输入错误 如果（haveHammer=false）

我想应该是双“=”的。编译不会对你大喊大叫，但逻辑不是你想要的

<>这个代码中有非C++代码，

    if (input == "hall..." || "ass" ）

在C++中，我们不使用它，尽管它是有效的。应该是

    if (input =="hall....") || input == "bbbb")

因为我认为您不会只想比较这些字符串文本的内存地址

---

（我没有仔细阅读代码，谢谢你的评论。

欢迎使用堆栈溢出！让人们发现代码中的错误不是特别有效。你应该使用调试器（或添加打印语句）要隔离问题，请跟踪程序的进度，并将其与预期发生的情况进行比较。一旦两者出现分歧，您就找到了问题。（然后，如果必要，您应该构建一个。）

它是漆黑一片。您很可能会被一只蛴螬吃掉。

这行是问题：

如果（haveHammer=false）“谢谢你，Oli，我会试试的。”Beovigt：一个不错的编译器会警告一个条件通常是预期的任务，即使类型是布尔型。<代码>输入<代码>是一个<代码>：ST:：String ，所以我们确实在C++中这样做，尽管如果我们想它工作，我们就做<代码>（（输入＝“Hall”）”（输入= =“ASS”）。

在C++

中我们不使用strcmp。在苏俄

strcmp

使用

C++

谢谢，这会清除一切！（当然，除了如何让它停止拆分我的字符串。我只需尝试谷歌：）每次查看getline以处理行。

    if (input =="hall....") || input == "bbbb")